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Airida [17]
2 years ago
10

Which of the following is an example of an adjusting entry?

Business
1 answer:
svetoff [14.1K]2 years ago
7 0

The correct answer is option A.  An example of an adjusting entry is Revenue that has been billed but not yet paid

<h3>What is an adjusting entry?</h3>

These are entries that share correct amount between income and expenditure in the period they occur, usually at the end of the financial period.

It is to be noted that adjusting entries are alteration made to journal entries that have been previously recorded.

Learn more about adjusting entries here: brainly.com/question/22635583

#SPJ1

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1. Bart Simpson, Inc., is considering the possibility of building an additional factory that would produce a new addition to its
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Answer:

Three cases are considered: First case is to construct a small factory, second is to construct a large factory and third is to do nothing.

Construct a Small Facility is the most suitable option from the business perspective which makes case 1 recommended.

Explanation:

Case 1 - Construct a small facility

Return = [P(High Demand) x Revenue in case of High Demand] + [P(Low Demand) x Revenue in case of Low Demand] - Cost of Setup

= [ 0.4 x 12 ] + [ 0.6 x 10 ] - 6 = $ 4.8 million

Case 2 - Construct a Large Facility

Return = [P(High Demand) x Revenue in case of High Demand] + [P(Low Demand) x Revenue in case of Low Demand] - Cost of Setup

= [0.4 x 14] + [0.6 x 10] - 9 = $ 2.6 million

Case 3 - Do Nothing

Return = 0  

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Which of the following is a good way to improve your credit score?
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Protect individuals from discrimination based on characteristics such as race, nationality, religion, and gender. These rights are guaranteed to all citizens under the due process and equal protection clauses of the United States Constitution and the laws of Congress.

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3 0
2 years ago
10. One drawback of a personal marketing survey is that A. the response time if rather long. B. respondents may misinterpret que
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A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by upper c equals 0.
Fantom [35]

Answer:

The cost per month is increasing at a rate $365.

Explanation:

Differentiation Formula

  • \frac{d}{dx}(x^n)= nx^{n-1}  
  • \frac{d}{dx}(a)=0             [ where a is a constant]
  • \frac{d}{dx}(ax^n)=a \frac{d}{dx}(x^n)= anx^{n-1}

Given that,

A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by

c=0.2x^2+10,000.

Again given that,

the rate of changing production is 13 unit per month

i.e \frac{dx}{dt}=13

To find the cost per month, we need to find out the value \frac{dc}{dt} when production is changing at the rate 13 units per month and the production is 70 units.

c=0.2x^2+10,000

Differentiating with respect to t

\frac{d}{dt}(c)=\frac{d}{dt}(0.2x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\frac{d}{dt}(x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\times 2x^{2-1}\frac{dx}{dt}+0

\Rightarrow \frac{dc}{dt}=0.4x\frac{dx}{dt}

Plugging \frac{dx}{dt}=13

\Rightarrow \frac{dc}{dt}=0.4x\times 13

\Rightarrow \frac{dc}{dt}=5.2x

\frac{dc}{dt}|_{x=70}=5.2\times 70 [ plugging x=70]

            =364

[ The unit of c is not given. Assume that the unit of c is dollar.]

The cost per month is increasing at a rate $365.

4 0
3 years ago
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