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andriy [413]
2 years ago
11

The following data depicts the relationship between the Amount spent on insurance and the amount of inventory loss.

Mathematics
1 answer:
Ahat [919]2 years ago
5 0

Using the given regression line, it is found that the amount of loss in inventory will be of $159.39.

<h3>What is the regression line?</h3>

The regression line is:

Y = 86.43 - 38.47X

In which:

  • X is the amount spent on protection.
  • Y is the amount of inventory lost.

In this problem, we have that X = $6.39, hence:

Y = 86.43 - 38.47 x 6.39 = -$159.39.

The amount of loss in inventory will be of $159.39.

More can be learned about regression lines at brainly.com/question/17004137

#SPJ1

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I need help with number 1
rjkz [21]

Answer:∠1=55° ∠2=55° ∠3=55° ∠4=70° ∠5=55°

Step-by-step explanation:

We know that opposite angles of rhombus are congruent and the diagonals of rhombus cut the vertex angles into half. So ∠4=70° and ∠2=∠3=∠1=∠5.

Let ∠2+∠3=x

the sum of four angles of rhombus= 360°

70+70+ x +x = 360°

140+2x = 360°

2x=220°

x=110°

∠2=110°/2=55°=∠3=∠1=∠5

3 0
3 years ago
What is the answer to it
andre [41]

No question?

Why not add one!

4 0
3 years ago
Shaun is picking out some movies to rent, and he is primarily interested in documentaries and mysteries. He has narrowed down hi
ycow [4]

Answer:

The total number of combinations in which the movies can be rented such that there is at least one documentary is 27589.

Step-by-step explanation:

The total movies are given as 19 mysteries +12 documentaries=19+12=31

Now the number of total combinations such that 4 movies are rented is given as ^{31}C_4=31465

Now the number of total combinations with no documentary is given as

^{19}C_4=3876

So the number of combination such that at least one movie is documentary is given as

=Total Combinations-Combinations with no documentary

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So the total number of combinations in which the movies can be rented such that there is at least one documentary is 27589.

7 0
4 years ago
Which graph shows a polynomial function with a negative leading coefficient?
VLD [36.1K]

Answer:

The first graph. (an upside down U)

Step-by-step explanation:

The leading coefficient of a polynomial determines the direction of the graph's end behavior.

A positive leading coefficient has the end behavior point up when an even degree and point opposite directions when an odd degree with the left down and the right up.

A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.

This graph has two evens. Because its negative, only one is possible - the first graph.

The other two graphs are odd with both starting down on the left and point up on the right which is a positive leading coefficient. These are not possible graphs.

The first graph is the solution.


4 0
3 years ago
Read 2 more answers
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