139, 149, 159, 169, 179, 189, 199, 209, 219, 229, 239, 249, 259.
The common difference is 13.
Let n = 52
Let d = common difference
a_52 = 139 + (52 - 1)(13)
a_52 = 139 + (51)(13)
a_52 = 139 + 663
a_52 = 802
Step-by-step explanation:
p1=7
p2=10
p3=13
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Answer:
Step-by-step explanation:
1 semester = 4474
8 semester = 8* 4474 35792
1 semester books = 389
8 semester books = 8* 389 <u> 3112 </u>
Total 38904
If he is going to pay this off in 10 years, he would have to have an increase of 3890.40 (after all income taxes) to pay it off. Fewer years would mean dividing by the number of years.
So for 8 years for example, he would need 4863 every year.
That number is obtained by dividing 38904 / 8
In 6 years he would need
38904/6 = 6484 extra dollars.
Do you need it explained or just the answer
Answer:
Step-by-step explanation:
To solve this, we are going to make an age table:
Age Now Age 10 years ago
Tanya
Elliot
Filling the in the Age Now column comes from the first sentence. If Elliot is 2 times Tanya's age and we don't know Tanya's age, then Tanya's age is x and Elliot's age is 2x:
Age Now Age 10 years ago
Tanya x
Elliot 2x
Filling in the Age 10 years ago column simply requires that we take their ages in the Age Now column and subtract 10 from each age:
Age Now Age 10 years ago
Tanya x x - 10
Elliot 2x 2x - 10
Since the question is How old is Elliot now based on the fact that 10 years ago....blah, blah, blah, we are using the ages in the 10 years ago column to write our equation. It says:
10 years ago, Elliot was 4 times as old as Tanya. Translated into mathspeak:
2x - 10 = 4(x - 10) and
2x - 10 = 4x - 40 and
-2x = -30 so
x = 15. That means that Elliot is 30 and Tanya is 15
