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PolarNik [594]
2 years ago
5

A cylindrical package to be sent by a postal service can have a maximum combined length and girth (perimeter of a cross section)

of 123 inches. Find the dimensions of the package of maximum volume that can be sent. (The cross section is circular.)
Mathematics
1 answer:
motikmotik2 years ago
3 0

The height of package is 34 inches.

According to the statement

we have given that the perimeter of cylinderical package is 123 inches.

and we have to find the volume of this package.

So,

According to the perimeter

2(Pi)r + h = 123

and then

h = 123 - 2(Pi)r

then the volume become

V = (Pi) r^2h

V= (Pi) r^2 * [ 123 - 2(Pi)r ] = 123 (Pi) r^2  - 2(Pi)r^3

then differentiate it

dV/dr = 246(Pi) r - 6(Pi)r^2

Now take

r(246(Pi) - 6(Pi)r) = 0

then neglect r=0 and then find another value of r.

r = 246(Pi) / 6(pi)

here r=41 then

h = 123 - 2(Pi)r

h = 123 - 2(3.14)41

h = 123 - 2(Pi)r

Then put the value of r then h = 34 inches.

So, The height of package is 34 inches.

Learn more about Volume here brainly.com/question/1972490

#SPJ4

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Use <u>Integration by Substitution</u>:

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Therefore:

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