The answer to the question is
5r= 28
r= 28/5
If we take the number of Zebras to be x and that of peacocks to be y
Then x + y = 14
A zebra has 4 legs while a peacock has 2 legs,
Therefore the total number of legs will be 4x + 2y which is equal to 36 .
Therefore, we have two equations
x + y = 14
4x + 2y = 36 solving them simultaneously using elimination
4x +2y = 36
2x + 2y = 28 ( multiplying the first equation by 2 to eliminate y)
2x = 8 ( subtracting the equations)
x = 4
y = 14 -(4)
= 10
Therefore, there are 4 zebras and 10 peacocks in the zoo
I did the math twice and it should be 45 I’m pretty sure
Answer:
not enough seats
Step-by-step explanation:
12 rows of 14 seats is ...
12 × 14 seats = 168 seats
8 rows of 12 seats is ...
8 × 12 seats = 96 seats
Then the total number of seats is ...
168 seats + 96 seats = 264 seats
This is fewer than 272, so there will not be enough seats for everyone.
Answer:
Step-by-step explanation:
you take 30% and 10% and turn them into decimal like so:
30/100=0.3
10/100=0.1
400.00(0.3)=120.00
120(0.1)=12
