Ratio would look like 20:36... Did you mean to put the numbers twice?
Answer:
Part A: x is the number of windows
company A=6x+12
companyB=5x+15
Part B
company B
Part C
$3
Step-by-step explanation:
Part B
A 6*8+12=60
B 5*8+15=55
Part C
(6*6+12)-(5*6+15)=3
For this case we have the following expression:
![\sqrt [3] {5x-2} - \sqrt [3] {4x} = 0](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5x-2%7D%20-%20%5Csqrt%20%5B3%5D%20%7B4x%7D%20%3D%200)
If we add to both sides of the equation
we have:
![\sqrt [3] {5x-2} = \sqrt [3] {4x}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B5x-2%7D%20%3D%20%5Csqrt%20%5B3%5D%20%7B4x%7D)
To eliminate the roots we must raise both sides to the cube:
![(\sqrt [3] {5x-2}) ^ 3 = (\sqrt [3] {4x}) ^ 3\\5x-2 = 4x](https://tex.z-dn.net/?f=%28%5Csqrt%20%5B3%5D%20%7B5x-2%7D%29%20%5E%203%20%3D%20%28%5Csqrt%20%5B3%5D%20%7B4x%7D%29%20%5E%203%5C%5C5x-2%20%3D%204x)
So, the correct option is the option c
Answer:
Option C
Hey! Sorry I couldn't type this out on here so here is the image!
Almost 60 years after taking my last math class, I discovered
how to turn a repeating decimal into its equivalent fraction.
-- Take the set of digits that repeats, no matter how many digits there are.
Write them as the numerator of a fraction.
-- For the denominator, write the same number of '9's.
-- If it's possible and you feel like it, simplify (reduce) the fraction.
You have 0.023 with the 23 (two digits) repeating forever.
-- Write the 23 (two digits) as the numerator.
-- Write 99 (two digits) as the denominator.
Now you have the fraction 23 / 99 . It can't be reduced.
You actually had 0.0... before the repeating part. That just
means that the fraction has been divided by 10. The real
equivalent fraction is 23 / 990 . (Which also can't be reduced.)
After so many years not knowing how to do it, this still blows my mind.
Just now, I punched " 23/990 "into my calculator, and stared in wonder
and amazement when " 0.023232323 " came up.