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2 years ago

15

Find the fifth term and the nth term of the geometric sequence whose initial term a, and common ratio r are given.

1 answer:

Goryan [66]2 years ago

5 0

Answer:

a₅ = 80 , $a_{n}$ = 5 $(2)^{n-1}$

Step-by-step explanation:

to find a term in the geometric sequence multiply the previous term by r

a₁ = 5

a₂ = a₁ × 2 = 5 × 2 = 10

a₃ = a₂ × 2 = 10 × 2 = 20

a₄ = a₃ × 2 = 20 × 2 = 40

a₅ = a₄ × 2 = 40 × 2 = 80

the nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

here a₁ = 5 and r = 2 , then

$a_{n}$ = 5 $(2)^{n-1}$

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Luke and Inga are riding the Prince Charming Carousel at Disney World. Luke is on a horse 17 feet from the center. Inga is on a

wlad13 [49]

Answer:

Luke's angular speed = 188.49 rad/sec

Inga's angular speed = 188.49 rad/sec

Step-by-step explanation:

Data provided in the question:

Distance between the center and Luke = 17 feet

Distance between the Inga and center = 25 feet

Frequency of rotation, f = 30 rpm

Now,

Angular speed, ω is given as = 2πf

thus,

ω = 2π × 30

or

ω = 188.49 rad/s

here the angular speed is independent of radius

Therefore,

Luke's angular speed = 188.49 rad/sec

Inga's angular speed = 188.49 rad/sec

7 0

3 years ago

TJ invested $4000 in a bond at a yearly rate of 2%. He earned $200 in interest. How long was the money invested

kow [346]

4000.00 x 2.0 = $80.00 per year x 2 years = $160.00 so 6 months would earn $40.00 taking it to the $200, so 2 yrs 6 mos.

3 0

3 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

3 years ago

Please answer correctly! I will mark you as Brainliest!

Hitman42 [59]

Multiply the length by width by the height/3

7 x 6 x 8/3 = 112 in^2

The answer is 112 in^2

8 0

3 years ago

Read 2 more answers

The graph shows the number of cases of bottles of water and the total number of bottles of water.

faltersainse [42]

Answer:

b = 24c

Step-by-step explanation:

6 0

3 years ago