The correct answer is - C. A male black bear eats fish in an area of a lake, so other black bears can't.
The intraspecific competition is a competition between the members of the same species for resources and territory. The indirect competition, in this case, would mean that the members from the same species do not get into a direct physical confrontation over the resources, but instead avoid each other and once one member occupies one place, the other one goes to another space that is not occupied.
In this case, with the black bear, the bear has occupied a spot at the lake where it feeds itself. Even though it is using the food resources, the other bears don't physically confront it, but instead pick another place on the lake that is free for using the same food resources.
The Vanderbilt University Institute for Imaging Science (VUIIS) Center for Computational Imaging (CCI) is known to have made a database built on XNAT housing that is said to house about a quarter of a million scans.
<h3>What is the institute about?</h3>
The above study was said go have used the database that gave a framework for:
- Fast prototyping
- large volume batch processing of images
- Scalable project management.
The above system is one that make use of the web-based interfaces of XNAT and REDCap to give room for graphical interaction.
Hence, the Distributed Automation for XNAT (DAX) package, is one that shares computation in all of Vanderbilt Advanced Computing Center for Research and Education high form of computing center.
Therefore, The Vanderbilt University Institute for Imaging Science (VUIIS) Center for Computational Imaging (CCI) is known to have made a database built on XNAT housing that is said to house about a quarter of a million scans.
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Answer:
4pi/3
Explanation:
XY = YZ = XZ = 2
angle YXZ is pi/3
wxy is 2pi/3
Area of the circle = pi*r^2 = 4pi
Area of the shaded area = 4pi * (2pi/3)/(2pi) = 4pi/3
The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
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