Answer:
$93,000
Explanation:
Data provided in the question:
selling cost of the property = $350,000
Earnest money paid = $12,000
Percentage of loan obtained = 70%
Now,
The amount of loan obtained = 70% of $350,000
= $245,000
Therefore,
Amount to be paid by self
= selling cost of the property - amount of loan obtained
= $350,000 - $245,000
= $105,000
Thus,
Additional cash the buyer will have to bring to the closing day
= Amount to be paid by self - Earnest money paid
= $105,000 - $12,000
= $93,000
Answer:
$7,200
Explanation:
According to the scenario, computation of the given data are as follows,
Total cost = $84,000
Salvage value = $12,000
Estimated life = 10 years
So, we can calculate depreciation expense by using following formula,
Depreciation yearly = (Total cost - Salvage value) ÷ Estimated life
= ($84,000 - $12,000) ÷ 10
= $72,000 ÷ 10
= $7,200
Answer:
We will consider positive interest rate which is i=0.21 or i=21%
Explanation:
The formula for Future value is:

The present value will become:

where:
n is the number of years
Since the condition is same present value,so the given data form the equation:

Divide above equation by 

Let
. Above equation will become:

Rearranging above equation:

Solving the quadratic equation:
z=1.1, z=0.9
Let
will become:


For z=1.1

For z=0.9

we will consider positive interest rate which is i=0.21 or i=21%