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GalinKa [24]
2 years ago
15

Given that the midpoints of pq is (-3,1) and q (7,5), obtain the co-ordinates of p

Mathematics
1 answer:
otez555 [7]2 years ago
4 0

The coordinates of P are (-13, -3), given the coordinates of Q as (7, 5) and the coordinates of the midpoint of PQ as (-3, 1).

The midpoint of AB,  given any points A (x₁, y₁) and B(x₂, y₂) is given as point M = ({(x₁ + x₂)/2},{(y₁ + y₂)/2}).

In the question, we are given that the midpoint of PQ is (-3, 1) and point Q is (7, 5).

We are asked to find the coordinates of point P.

We assume the coordinates of point P as (x, y).

Thus, the midpoint of PQ = ({(x + 7)/2}, {(y + 5)/2}),

that is, (-3, 1) = ({(x + 7)/2}, {(y + 5)/2}).

Thus, we can show that:

(x + 7)/2 = -3,

or, x + 7 = -6,

or, x = -6 - 7 = -13.

(y + 5)/2 = 1,

or, y + 5 = 2,

or, y = 2 - 5 = -3.

Thus, the coordinates of P are (-13, -3), given the coordinates of Q as (7, 5) and the coordinates of the midpoint of PQ as (-3, 1).

Learn more about midpoints at

brainly.com/question/4521677

#SPJ4

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Answer:

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Step-by-step explanation:

8 1
3 years ago
What is the simplified form of the expression? k3 [k^7/3] -5
iragen [17]
Simplify the following:
(k^3 k^7)/3 - 5

Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5

7 + 3 = 10:
k^10/3 - 5

Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3

k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3
3 0
3 years ago
1/2 + 5/3 - 1<br>------------------<br> 3/4
Sav [38]
Hey there :)

\frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} }
      ↓ Is the same as
\frac{1}{2} + \frac{5}{3} -1 ÷ \frac{3}{4}

Since it is a division by fraction, we can multiply by what is called the reciprocal
( The attached picture might help you )
( \frac{1}{2} + \frac{5}{3} - 1 ) × \frac{4}{3} 
     ↓ For this part, we need the common denominator, which is 6
\frac{1(3)}{2(3)}+ \frac{5(2)}{32)}  \frac{1(6)}{1(6)} × \frac{4}{3}

\frac{3}{6}+ \frac{10}{6}  - \frac{6}{6} × \frac{4}{3}
\frac{7}{6} × \frac{4}{3}
\frac{14}{9} =  1\frac{5}{9}
  ↑
Your final answer
 

7 0
3 years ago
I really had some trouble with this problem:( &amp; I need some help
Natasha_Volkova [10]
The answers are in the photo

7 0
2 years ago
In a certain month, Mason spent 1/6 of his salary in the first three days and $800 in the following ten days and after that he w
Nesterboy [21]
<h3>Answer:   $2400</h3>

========================================================

Explanation:

x = Mason's salary in dollars for that month

x/6 = one-sixth of his salary

x/6+800 = total amount spent (the x/6 dollars and $800 combined)

In total, he spent half his salary. This means he spent x/2 dollars for the month overall.

Set the two items equal to one another. Solve for x.

x/6 + 800 = x/2

6(x/6 + 800) = 6*(x/2) ... see note at the bottom of the page

x+4800 = 3x

4800 = 3x-x

4800 = 2x

2x = 4800

x = 4800/2

x = 2400

His monthly salary is $2400

1/6 of this is (1/6)*2400 = 2400/6 = 400 dollars. Add on the $800 he also spent to get a total of 400+800 = 1200 dollars spent, which is exactly one half of the $2400. The answer is confirmed.

-------

Note: I multiplied both sides by 6 to clear out the fractions. The value 6 is the LCD in this case.

7 0
3 years ago
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