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1 year ago

I really had some trouble with this problem:( & I need some help

Mathematics

1 answer:

Natasha_Volkova [10]1 year ago

7 0

The answers are in the photo

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5/2 x X =1 what’s the answer

nata0808 [166]

Answer: X is 0.4

Explanation: I typed 5/2 x a bunch of random numbers and decimals on a calculator until I tried 0.4 and when I typed 5/2 x 0.4 on the calculator it said 5/2 x 0.4 = 1.

5 0

2 years ago

Read 2 more answers

Evaluate the limit, if it exists. (if an answer does not exist, enter dne.) lim h → 0 (−6 + h)2 − 36 h

Lyrx [107]

The limit can be found by simplifying the expression.
$\lim\limits_{h\rightarrow 0}\left(\dfrac{(-6+h)^{2}-36}{h}\right)=\lim\limits_{h\rightarrow 0}\left(\dfrac{-12h+h^{2}}{h}\right)\\\\=\lim\limits_{h\rightarrow 0}(-12+h)\\\\=-12$

The limit is -12.

3 0

3 years ago

Read 2 more answers

I found a place that will give me a 20 percent discount if i spend over 50 dollars. My bill is 75 dollars. How much money will i

const2013 [10]

X of 20% = y
x - y = 75

x = total amount
y = discounted amount

x * 20/100 = y
x * 0.2 = y
replace y with 0.2x in other equation

x - y = 75
1x - 0.2x = 75
0.80x = 75
x = 75/.8
x = 93.75

Check:
93.75 * 20/100 = 18.75
93.75 - 18.75 = 75
x = 93.75
y = 18.75

Answer: Total amount without discount is $93.75

//BTW not sure about this, but kind of make sense

6 0

3 years ago

Find the midpoint of the line segment joining points A and B. A(2, - 5); B(4,1)

Nookie1986 [14]

Answer:

(3, -2)

Step-by-step explanation:

Find the midpoint coordinates (x, y) of points A(2, - 5) and B(4, 1)

x-coordinate of the midpoint is (2+4)/2 = 6/2= 3

y-coordinate of the midpoint is (-5+1)/2 = -4/2= -2

The mid point coordinates are (3, -2)

6 0

3 years ago

Show work and explain with formulas:

Marina86 [1]

17 Answer: 205

Step-by-step explanation:

$\{1\dfrac{2}{3}+1\dfrac{5}{6}+2+...+8\dfrac{1}{3}\}\implies a_1=1\dfrac{2}{3},\ d=\dfrac{1}{6}\\\\\\a_n=a_1+d(n-1)\qquad solve\ for\ n\\\\8\dfrac{1}{3}=1\dfrac{2}{3}+\dfrac{1}{6}(n-1)\\\\\\\dfrac{25}{3}=\dfrac{5}{3}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{50}{6}=\dfrac{10}{6}+\dfrac{1}{6}n-\dfrac{1}{6}\\\\\\\dfrac{41}{6}=\dfrac{1}{6}n\\\\\\\dfrac{41}{6}\cdot 6=n\\\\41=n$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{41}=\dfrac{1\dfrac{2}{3}+8\dfrac{1}{3}}{2}\cdot 41\\\\\\.\quad =\dfrac{10}{2}\cdot 41\\\\\\.\quad =5\cdot 41\\\\.\quad =\large\boxed{205}$

18 Answer: 1968

Step-by-step explanation:

$a_1=-6,\ d=2,\ n=48, \quad \text{solve for }a_{48}\\\\a_{n}=a_1+d(n-1)\\\\a_{48}=-6+2(48-1)\\\\.\quad =-6+2(47)\\\\.\quad =-6+94\\\\.\quad =88$

$\text{Now use the sum formula:}\\\\S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{48}=\dfrac{-6+88}{2}\cdot 48\\\\\\.\quad =\dfrac{82}{2}\cdot 48\\\\\\.\quad =41\cdot 48\\\\.\quad =\large\boxed{1968}$

19 Answer: -116

Step-by-step explanation:

$\{3, -2, -7, ...\}\\a_1=3,\ d=-5,\ n=8, \quad \text{solve for }a_{8}\\\\a_{n}=a_1+d(n-1)\\\\a_{8}=3-5(8-1)\\\\.\quad =3-5(7)\\\\.\quad =3-35\\\\.\quad =-32\\\\\text{Now use the sum formula:}\\\\S_8=\dfrac{a_1+a_8}{2}\cdot 8\\\\\\S_{8}=\dfrac{3-32}{2}\cdot 8\\\\\\.\quad =\dfrac{-29}{2}\cdot 8\\\\\\.\quad =-29\cdot 4\\\\.\quad =\large\boxed{-116}$

6 0

3 years ago