5*8+2
When a letter is next to a number u multiply
5*8+2=42
c: number of carnations
r: number of roses
Rebecca's expression is
r = c + 4
Replacing with the values of the table:
c | r
0 | 0+4 = 4
1 | 1+ 4 = 5
2 | 2+4 = 6
3 | 3+4 = 7
4 | 4+4 = 8
Then, Rebecca is correct.
Isolating c from Rebecca's expression:
c = r - 4
which is Austin's expression. Then, Austin is correct too.
Answer:
Step-by-step explanation:
Since the slope is -5 is either C or D. Let's replace 
in either to see what we get.
C: 
Nope.
D: 
Good!
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
