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sergij07 [2.7K]
3 years ago
14

Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1 and the given zeros for

3, 5+ square root of 5
Mathematics
1 answer:
timama [110]3 years ago
7 0
The general form of a polynomial is: x² + bx + c = 0. Substituting the roots,

3² + b(3) + c = 0
3b + c = -9 --> eqn 1

(5 + √5)² + (5 +√5)(b) + c = 0
(5+√5)b + c = -30-10√5 --> eqn 2

Solving both equations simultaneously by subtracting eqn 2 from eqn 1,
(-2 - √5)b = 21 + 10√5
b = -8 - √5

Using eqn 1,
3(-8 - √5) + c = -9
-24 - 3√5 + c = -9
c = -9 + 24 + 3√5
c = 15 + 3√5

Hence, the polynomial is: <em>f(x) = x² + (-8 - √5)x + (15 + 3√5)</em>.
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Part 1: Write the equation of the line that passes through the points (–1, –4) and (2, 5).
jeyben [28]
Y - (-4) = (5 - (-4))/(2 - (-1)) (x - (-1))
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3 years ago
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A school debate team has four girls and six boys. A total of four of the team members will be chosen to participate in the distr
alex41 [277]
Procedure:

1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)

Solution

1) the number of teams of four members that can be formed are:

10*9*8*7 / (4*3*2*1) = 210

2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls

Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6

Number of different teams with 2 boys and 2 girls = 15 * 6 = 90

3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:

90/210 = 3/7
 
7 0
3 years ago
Evaluate -29 - X<br> when x = 6
notka56 [123]

Answer:

wouldn't that just be -35?

Step-by-step explanation:

you just have to do -29-6

6 0
3 years ago
X is called the _____ When using scientific notation the _____ is 10.​
Bumek [7]

Answer:

X is called the power of

1 is 10

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3 years ago
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