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Otrada [13]
2 years ago
5

Help pls :’( ASAPP!!! “Complete the proof”

Mathematics
1 answer:
nata0808 [166]2 years ago
6 0

1) \overline{AB} \cong \overline{CD}, \overline{AD} \cong \overline{CB}, \overline{AX} \perp \overline{BD}, \overline{CY} \perp\overline{BD} (given)

2) \overline{BD} \cong \overline{BD} (reflexive property)

3) \triangle ABD \cong \triangle ACDB (SSS)

4) \angle ADB \cong \angle CBY (CPCTC)

5) \angle CYB and \angle AXD are right angles (perpendicular lines form right angles)

6) \triangle CYB and \triangle AXD are right triangles (a triangle with a right angle is a right triangle)

7) \triangle AXD \cong \triangle CYB (HA)

8) \overline{AX} \cong \overline{CY} (CPCTC)

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Pls answer i need answer fast
puteri [66]

Answer:

-24

Step-by-step explanation:

Given expression:

      3z (2y - 4)²

  z = -2 and y = 3

To solve this problem, simply substitute:

       3z (2y - 4)² = 3(-2){2(3) - 4}²

                           = -6(6-4)²

                           = -6 (2)²

                          = -6 x 4

                          = -24

3 0
3 years ago
Read 2 more answers
Heyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy (got to match my vibe to answer)
Bas_tet [7]

Answer:

2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)

Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?

ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol

5 0
3 years ago
Read 2 more answers
The head of the Westlane Cultural Center wants to get a sense of how quickly pledges from donors arrive at the center. It takes
Rzqust [24]

Answer:

95.64% probability that pledges are received within 40 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 28, \sigma = 7

What is the probability that pledges are received within 40 days

This is the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 28}{7}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564

95.64% probability that pledges are received within 40 days

7 0
3 years ago
D is not right its a negative 8 so therefore it would be minus
Ilya [14]
I really dont understant your question. but you are right that negative 8 that it would be minus. <span>In </span>mathematics<span>, a </span>negative<span> number is a real number that is less than zero. </span>Negative<span> numbers represent opposites. If positive represents movement to the right, </span>negative<span> represents movement to the left.</span>
6 0
3 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
3 years ago
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