Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or
ft
=
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
=
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k(
)
k = 18
Work done (W) to stretch the spring by
ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9(
)²
= 7.56 lb-ft
Answer:
Just substitue every 't' with -4
Step-by-step explanation:
g(-4) = 3*(-4)*(-4) + 2*(-4) + 1
g(-4) = 64-8+1
g(-4) = 57
Maybe the second one or third one
Answer:
x= -3 , -7
Step-by-step explanation:
Answer:
Approx. 6 b/m
Step-by-step explanation:
Find out How many minutes in a year which is 525600 then divide that by 3,000,000 which makes 5.7077 so rounded is 6.