Answer:
D
Step-by-step explanation: When you plug 3 into where x in the first equation and plug 2 in for y. When you do that you get 6-2<5, 6-2 is 4 and 4 is less than 5, so this makes this equation true. For the second equation you do the same. 3 goes into the x spot and 2 into the y, after doing this you get 3+2(2)>2, 3 times 4 is 12 and that is greater than 2, hich also means that equation is ture. So there you have both equations are ture and that is how you get your answer.
We could say that every 2 years, Patrick gains 7 kg (after reaching a certain age under 12) making it
7(y/2) (if y = every year after the age given, and we divide by 2 because it's every 2 years, not one)+w (patrick's weight at the start)= w (weight)
B- We could say that w(current weight)+100000=b (new weight)
C - If patrick weighed 43 kg when he was 12 , how much would he weigh when he was 20?
D - Using the correct equation, we have 7(20/2-12/2)+43=7(4)+43=28+43=61
Using the incorrect equation, we have 43+100000=100043 kg
Answer:
c) 75, 2
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sampling distribution of the sample mean, with a large sample size, can be approximated to a normal distribution with mean
and standard deviation
.
In this problem, we have that:
Records show that the weights of boxes that it carries have a mean of 75 lb and a standard deviation of 16 lb. This means that
.
For sample size of 64, find the mean and standard deviation of x bar
We have that
.
So the correct answer is:
c) 75, 2
Do you still need help on this?
On monday William watered: 1/5 of his plants
On tuesday William watered: 1/5 of his plants
1/5+1/5=2/5 He watered 2/5 of his plants.
2/5+x=1
2/5+x=5/5, x=5/5-2/5, x=3/5
William still needs to water 3/5 of his plants.