5 in each bunch there will be 7 spots and ther ewill be five ballones in each spot
It is not linear because x is raised to the second power. Therefore it is not straight and would be kindof like a rainbow cut in half on the graph..
Multiply the whole numbers as usual. then find the gcf and divide for how many times the denominator can go into the gcf. gcf for 1/5 and 2/3 is 15 but Idk how to deal with the numerator.
Answer:
y = 10(½)^(x)
Step-by-step explanation:
In writing exponential functions passing through points, we will just substitute the x and y values in each case into y = ab^(x).
Now, for point (-1, 20), the exponential function is; 20 = ab^(-1)
20 = a/b
For the point (1, 5), the exponential function is; 5 = ab^(1)
5 = ab
From 20 = a/b, we have; a = 20b
Thus, putting 20b for a in 5 = ab, we have;
5 = 20b(b)
b² = 5/20
b² = 1/4
b = √(1/4)
b = 1/2
Since a = 20b, then;
a = 20 × 1/2
a = 10
Thus, from y = ab^(x), we have;
y = 10(½)^(x)
<u>Answer</u>:
25) If f(x) = sin ([1/3] x) , find f(π/2).
Substitute with x = π/2
f(π/2) = sin ([1/3] *[π/2]) = sin (π/6) = 1/2
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26) If f(x) = cos (2x) , find f(3π/4).
Substitute with x = 3π/4
f(3π/4) = cos ( 2 * 3π/4) = cos ( 3π/2) = zero.
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27) If f(x) = sin (2x) + cos (3x) , find f(π/4)
Substitute with x = π/4
f(π/4) = sin ( 2 * π/4) + cos ( 3 * π/4) =
= sin ( π/2) + cos ( 3π/4)
= 1 - 1/(√2)
= 0.293
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28) f(x) = tan (5x) - sin (2x) , find f(π/6).
Substitute with x = π/6
So, f(π/6) = tan (5 * π/6) - sin ( 2 * π/6)
= tan (5π/6) - sin (π/3)
= -1/(√3) - (√3)/2
= -1.443