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3 years ago

Solve for z in the literal equation – (z +11)=y.

Mathematics

2 answers:

Sergeu [11.5K]3 years ago

4 0

Answer:

z=-y-11

Step-by-step explanation:

let's take out the parenthesis

-z-11=y

Now put 11 on the other side

-z=y+11

Then make z positive

z=-y-11

Nana76 [90]3 years ago

4 0

The answer is : z=−y−11

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2 years ago

If a = -9 and b = 4, what is the value of a + b ?<br> A. -5<br> B. 5 <br> C. -13 <br> D. 13

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3 years ago

7. The probability that a randomly chosen student will be left-handed is .09: a) In a class of 108, find the probability that th

vampirchik [111]

Solution :

Let x be student will be left handed

P = 0.09

Using the normal approximation to binomial distribution,

a). n = 108,

μ = np = 9.72

$\sigma = \sqrt{np(1-p)}$

$=\sqrt{8.8452}$

= 2.9741

Required probability,

P(x=8) = P(7.5 < x < 8.5)

$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$

$=P(-0.75 < z < -0.41)$

Using z table,

= P(z<-0.41)-P(z<-0.75)

= 0.3409-0.2266

= 0.1143

b). P(x=12) = P(11.5 < x < 12.5)

$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$

$=P(0.60 < z < 0.94)$

Using z table,

= P(z< 0.94)-P(z< 0.60)

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2 years ago

Raman mixed juice and water in the ratio 2 : 3 and Meera mixed juice and water in the ratio 1 : 4. They then mixed 150 ml of Ram

Kay [80]

Answer:

Step-by-step explanation:

ramans ratio is 2:3

so in 150ml there are 2 parts of juice and 3 parts of water

2x + 3x = 150

x = 30

so, juice in 150 ml of raman's mixture = 2x = 2* 30 = 60ml

meera ratio is 1:4

similarly,

1y + 4y = 100

y = 20

so, juice in 100 ml of meera's mixture is y = 20ml

so, quanitity of juice in final mixture is 60 + 20 = 80

4 0

2 years ago

Solve for z in the literal equation – (z +11)=y.​

Solve for z in the literal equation – (z +11)=y.