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choli [55]
2 years ago
8

Strictly speaking pure competition is relatively rare. then why do we study it

SAT
1 answer:
ivanzaharov [21]2 years ago
3 0

The study of pure competition in economics is because it describes a perfect situation of low-cost production and allocative efficiency which serves as a criteria of comparison.

<h3>What is pure competition in economics?</h3>

Pure competition in economics is the study of the marketing situation in where a large number of sellers of a similar product such that no significant influence on price is produced by any one firm.

The study of pure competition serve as as basis of comparison as it produces ideal results.

In conclusion, pure competition serves as a criteria for comparison.

Learn more about pure competition in economics at: brainly.com/question/1964924

#SPJ1

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A beaker about two-thirds full of a liquid. check all that apply. pour using tongs. wear chemical resistant gloves. taste to mak
jekas [21]

A beaker about two-thirds full of a liquid. check all that apply. pour using tongs. wear chemical resistant gloves. taste to make sure it is hcl. One should wear chemical resistant gloves.

It is not at all possible to pour the liquid with the help of tongs because it may spill and cause harm, in case it is hazardous.

Also tasting whether the liquid is hcl or not is not gonna help because we don't know whether the chemical is fatal or not. Even if it is Hcl, tasting it is not a good option, because it will cause damage to our tongue and other parts of mouth.

Thus the most convenient thing to do is to wear chemical resistant gloves to ensure safety.

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2 years ago
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Komok [63]
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If a person takes 30 ml of vinegar a day and the molarity of the vinegar is 0. 84 m then how many grams of acetic acid (hc2h3o2
babunello [35]

The mass of the acetic acid is 1.512 g.

<h3 /><h3>What is Molarity?</h3>

molarity is the concentration of a substance in mol per dm³

From the question,

The number of moles contained in the 30 mL vinegar is

  • n = (0.84×30)/1000
  • n = 0.0252 mol.

the molar mass of vinegar is calculated below.

  • m.m of (HC₂H₃O₂) = [1+(12×2)+(1×3)+(16×2)]
  • m.m = (1+24+3+32]
  • m.m = 60 g/mol.

To calculate the mass of acetic acid, we use the formula below.

  • R.m = n×m.m............. Equation 1

Where

  • R.m = mass of acetic acid.

Substitute these values into equation 1

  • R.m = (0.0252×60)
  • R.m = 1.512 g.

Hence, The mass of the acetic acid is 1.512 g.

Learn more about molarity here: brainly.com/question/20383725

8 0
3 years ago
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