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kykrilka [37]
2 years ago
5

Which of the following statements regarding the moon and earth is correct.

SAT
1 answer:
hoa [83]2 years ago
7 0

Answer:

please the question is choice or what

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A candle slowly burns until the last bit of wax and wick are gone.
Andru [333]

Answer:

1) B. The change in energy in a system during an exothermir reaction

2) B. In the air, only the oxygen is part of the system

3) B. The energy found in the reactants....

4) D. This is an endothermic reaction because the system took energy from the surroundings.

5) B. Energy is released by the formation of chemical bonds

Explanation:

TOOK THE QUIZ...YOU'RE WELCOME!!!

3 0
2 years ago
20 points and will mark brainliest!
mina [271]

the answer is 7. false

6 0
3 years ago
Read 2 more answers
Part 2
ss7ja [257]

Explanation:

12: life line for commoners

13.started riot, especially

14.unfaur taxation, voting issues, unequal lang, estates gets all the votes, 1st and 2nd estates more votes than 3rd estates.

15. most of the population who were the 3rd estates (97%) treated people poorly with high taxes and decided to revolt

8 0
3 years ago
Calculate the mass of hydrogen in 57. 010 grams of ammonium hydrogen phosphate.
erastovalidia [21]

The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g  

<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>

1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g

<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>

Mass of H = 6H = 6 × 1 = 6 g

<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>

115 g of (NH₄)H₂PO₄ contains 6 g of H.

Therefore,

57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H

Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄

Learn more about mass composition:

brainly.com/question/13531044

4 0
3 years ago
A college-bound student is least likely to participate in which of these CTSOs?
djyliett [7]

Answer:

a

Explanation:

6 0
3 years ago
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