Question

Could someone please draw the triangle based off of this description

Answer 1

The altitudes of equal length, BE and CF gives AB = AC, from which we have;

• ∆ABC is an isosceles triangle

How can the RHS rule be used to indicate an isosceles triangle?

From the given description, we have;

BE = CF

<CFB = <BEC = 90° All right angles are congruent

BC = BC by reflexive property of congruency

BC = The hypotenuse side of triangles ∆BFC and ∆CEB

Therefore;

∆BFC is congruent to ∆CEB by Right angle Hypotenuse Side, RHS, rule of congruency.

Therefore;

BF = CE by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

Similarly, we have;

∆AEB is congruent to ∆AFC, by Side-Angle-Angle, SAA, rule of congruency

Which gives;

FA = AE by CPCTC

BF + FA = CE + AE, by substitution property of equality

BF + FA = AB

CE + AE = AC

Therefore;

• AB = AC

Therefore;

• ∆ABC is an isosceles triangle

Learn more about rules of congruency here:

brainly.com/question/24261247

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