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ehidna [41]
2 years ago
13

Given: Quadrilateral PAST, TX = AX; TP || AS Prove: Quadrilateral PAST is a parallelogram.

Mathematics
1 answer:
poizon [28]2 years ago
8 0

1) Quadrilateral PAST, TX=AX, \overline{TP} \parallel\overline{AS} (given)

2) \angle XPT \cong \angle XSA and \angle XTP \cong \angle XAS (alternate interior angles theorem)

3) \triangle TXP \cong \triangle AXS (AAS)

4) \overline{TP} \cong \overline{AS} (CPCTC)

5) PAST is a parallelogram (a quadrilateral with two pairs of opposite congruent sides is a parallelogram)

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71.42

Step-by-step explanation:

Percentage change:×100%

Now, the change is given from 42 acres to 72 acres, therefore

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4 years ago
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Step-by-step explanation:

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4 years ago
a 42 inch diameter tablecloth that hangs off the edge 8 inches. what is the area of the tablecloth use 3.14 for pi​
joja [24]

Answer: 1384.74

Step-by-step explanation:

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3 0
3 years ago
Mrs. Smith decides to buy three sweaters and a pair of jeans. she had $120 in her wallet. if the price of jeans is $45,
ale4655 [162]

Answer:

3s+2j\leq $120. The sweaters cost $10 or less each. We graph it on a number line at 10 and use a filled in dot pointing towards zero for less than.

Step-by-step explanation:

Mrs. Smith buys 3 sweaters (represented by 3s) and 2 jeans (represented by 2j) for a total of at most $120. We don't know the total but we do know she couldn't spend more than $120.

We write 3s+2j\leq $120.

We know the jeans cost $45 each, so j=45. We substitute,

3s+2(45)\leq $120\\3s+90\leq $120

We solve for s by subtracting 90 to the other side and dividing the result by 3.

3s+90-90\leq 120-90\\3s\leq 30\\\frac{3s}{3}\leq\frac{30}{3}

s\leq 10.

The sweaters cost $10 or less each.


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3 years ago
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Answer:

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Step-by-step explanation:

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6 0
2 years ago
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