Height of the water increasing is at rate of 
<h3>How to solve?</h3>
With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

In the problem, we are given
So we need to substitute this in:

Hence, Height of the water increasing is at rate of 
<h3>Formula used: </h3>

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Answer: 9.8 inches
Step-by-step explanation:
Since x = 2 inches
Rainfall in April = x inches = 2 inches
Rainfall in May = x + 1.3 = 2 + 1.3 = 3.3 inches
Rainfall in June = 2x + 0.5 = 2(2) + 0.5 = 4.5
Total rainfall = 2 + 3.3 + 4.5 = 9.8 inches
It’s 9 but are you serious
A=b/c -b/d
a+b/d=b/c
(da+b)/d=b/c
db=(da+b)c
c=db/da+b