Answer:What is the 11th term of this geometric sequence 5, 20, 80, 320? In the present GP, a = 5 and r = 20/5 = 4. So the 11th term of the GP = ar^10 = 5*4^10 = 5242880.
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
It matches the most
Answer:
3k^3 + k^2 - 4k
Step-by-step explanation:
k * 3k^2 = 3k^3
k * k = k^2
k * -4 = -4k
3k^3 + k^2 - 4k
Solution
Here the first term = -2
5th term = -1/8
Now we have to find the common ratio (r)
Fifth term A5 = -1/8
-1/8 =
Here
Plug in in the fifth term and find the value of r.
-1/8 = -2
Taking 4th root, we get
r =
Now let's find the second term.
first term *r = -2 *1/2 = -1
2nd term = -1
3rd term = second term * 1/2 = -1 * 1/2 = -1/2
4th term = 3rd term *r = -1/2 *1/2 = -1/4
Thank you :)
Answer:
We have to divide 3/5 which is 0.6 or 60% chance
Step-by-step explanation: