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1 year ago

14

A trapezoid has bases with lengths of 1.5 yards and 4 yards. The height is 12 yards. What is the area of the trapezoid?

1 answer:

Georgia [21]1 year ago

4 0

Answer: 33 square yards

Explanation: To solve this, we must first add both bases together, 1.5 and 4.

1.5 + 4 = 5.5

Next, we must multiply 5.5 and 12

12 x 5.5 = 66

The last step is to divide our product by 2, similar what we do to triangles.

66/2 = 33
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Hope this helps!!

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2 years ago

The cost of a company picnic varies directly as the number of employees attending the picnic. If a company picnic costs $487.50

Drupady [299]

The company picnic cost $ 1300 for 80 employees

<em><u>Solution:</u></em>

Given that cost of a company picnic varies directly as the number of employees attending the picnic

Let "c" be the company picnic cost

Let "n" be the number of employees attending the picnic

Therefore,

$cost \propto \text{ number of employees attending picnic }$

$c \propto n\\\\c = kn$

Where "k" is the constant of proportionality

c = kn ---------- eqn 1

<em><u>Given that company picnic costs $487.50 for 30 employees</u></em>

Therefore substitute c = 487.50 and n = 30

$487.50 = k(30)\\\\k = \frac{487.50}{30} = 16.25$

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2 years ago

How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50

Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of $\frac{5}{6}$ kilogram of candy is $7.5

- We need to find the cost of $4\frac{5}{7}$ kilogram

We can use the ratio to find the answer

======= Dollar : Kilogram

======= 7.5 : $\frac{5}{6}$

======= c : $4\frac{5}{7}$

By using cross multiplication

∴ c × $\frac{5}{6}$ = 7.5 × $4\frac{5}{7}$

∵ $4\frac{5}{7}$ = $\frac{4*7+5}{7}$

∴ $4\frac{5}{7}$ = $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = 7.5 × $\frac{33}{7}$

∴ c × $\frac{5}{6}$ = $\frac{495}{14}$

Divide both sides by $\frac{5}{6}$

∴ c = $\frac{495}{14}$ ÷ $\frac{5}{6}$

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = $\frac{495}{14}$ × $\frac{6}{5}$

∴ c = $\frac{297}{7}$ = 42.43 dollars

∵ c represents the cost of $4\frac{5}{7}$ kg

∴ It costs $42.43

7 0

2 years ago