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Margaret [11]
3 years ago
6

Hirva stopped to get gas and noted the milage on her car was 23,615. The next time she stopped to get gas, the mileage was 24,25

5 . If she bought 20 gallons of gas to fill her tank , how many miles per gallon is the car getting?
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0
6 4  0. says sister (big sister in highschool)
so if she gets it wrong i will help you out,without my sister answering......
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Name the plane represented by the top of the box.
Licemer1 [7]

Answer:

BCD

Step-by-step explanation:

The top rectangle is ABCD because of its vertices.  BCD is included in it.

6 0
3 years ago
13/100 + 11/10 helpppp
zhannawk [14.2K]

Answer:

13/100 + 11/10 = 123/100

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What's the area of a circle with diameter 18 units? Question 8 options: A) 9π units2 B) 81π units2 C) π units2 D) 18π units2
Anna [14]

Answer:

B) 81π units²

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Radius of a Circle Formula: r = d/2

  • r is radius
  • d is diameter

Area of a Circle Formula: A = πr²

Step-by-step explanation:

<u>Step 1: Define</u>

Diameter <em>d</em> = 18 units

<u>Step 2: Manipulate Variables</u>

Radius <em>r</em> = 18 units/2 = 9 units

<u>Step 3: Find Area</u>

  1. Substitute in <em>r</em> [Area of a Circle Formula]:                                                       A = π(9 units)²
  2. [Area] Evaluate exponents:                                                                              A = π(81 units²)
  3. [Area] Multiply:                                                                                                  A = 81π units²
6 0
2 years ago
A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est
xxTIMURxx [149]

Answer:

Point estimate for the population variance = 3.92 * 10^{-3} .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

       X                       X - Xbar                                         (X-Xbar)^{2}

      1.13            1.13 - 1.188 = -0.058                                 3.364 * 10^{-3}

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}    

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}

      1.24           1.24 - 1.188 = 0.052                                 2.704 * 10^{-3}

      1.27           1.27 - 1.188 = 0.082                               <u>  6.724 * </u>10^{-3}<u>    </u>

                                                                    \sum (X-Xbar)^{2} <u>= 0.01568   </u>

Firstly, Mean of above data, Xbar = \frac{\sum X}{n} = \frac{1.15+1.24+1.15+1.27+1.13}{5} = 1.188

Point estimate of Population Variance = Sample variance

                                                               = \frac{\sum (X-Xbar)^{2}}{n-1} = \frac{0.01568}{4} = 3.92 * 10^{-3} .

Therefore, point estimate for the population variance = 3.92 * 10^{-3} .

       

5 0
3 years ago
Read 2 more answers
Mr. Smith is flying his single-engine plane at an altitude of 2400 feet. He sees a cornfield at an angle of depression of 30º. W
Svet_ta [14]

Answer:

Height of the fighter plane =1.5km=1500 m

Speed of the fighter plane, v=720km/h=200 m/s

Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.

Muzzle velocity of the gun, u=600 m/s

Time taken by the shell to hit the plane =t

Horizontal distance travelled by the shell =u

x

t

Distance travelled by the plane =vt

The shell hits the plane. Hence, these two distances must be equal.

u

x

t=vt

u Sin θ=v

Sin θ=v/u

=200/600=1/3=0.33

θ=Sin

−1

(0.33)=19.50

In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.

H

max

=u

2

sin

2

(90−θ)/2g=600

2

/(2×10)=16km

4 0
3 years ago
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