Answer:
Thx
Step-by-step explanation:
Merry Christmas
Answer: The approximate absentee rate that day would be 8.09%.
Step-by-step explanation:
Since we have given that
Number of students who were absent = 36
Total number of students = 445
We need to find the approximate absentee rate that day :
Rate of absentee of that day would be
![\dfrac{\text{Number of absentee}}{\text{Total number of students}}\times 100\\\\=\dfrac{36}{445}\times 100\\\\=8.09\%](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BNumber%20of%20absentee%7D%7D%7B%5Ctext%7BTotal%20number%20of%20students%7D%7D%5Ctimes%20100%5C%5C%5C%5C%3D%5Cdfrac%7B36%7D%7B445%7D%5Ctimes%20100%5C%5C%5C%5C%3D8.09%5C%25)
Hence, the approximate absentee rate that day would be 8.09%.
Answer:
95% Confidence interval: (0.0429,0.0791)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 679
Number of anonymous websites, x = 42
![\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%20%3D%20%5Cdfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cdfrac%7B42%7D%7B679%7D%20%3D%200.0618)
95% Confidence interval:
![\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%5Cpm%20z_%7Bstat%7D%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
![z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96](https://tex.z-dn.net/?f=z_%7Bcritical%7D%5Ctext%7B%20at%7D~%5Calpha_%7B0.05%7D%20%3D%20%5Cpm%201.96)
Putting the values, we get:
![0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)](https://tex.z-dn.net/?f=0.0618%5Cpm%201.96%28%5Csqrt%7B%5Cdfrac%7B0.0618%281-0.0618%29%7D%7B679%7D%7D%29%20%3D%200.0618%5Cpm%200.0181%5C%5C%5C%5C%3D%280.0429%2C0.0791%29)
is the required confidence interval for proportion of all new websites that were anonymous.
Answer:
x>22
Step-by-step explanation:
Solve the inequality:
-3x<-14-52
-3x<-66
x>22
( You have to switch the sign because you are dividing by a minus)