Answer:
Evaluation of the integral part of the quotient of division by 2
Step-by-step explanation:
If shifting left by 1 bit is equivalent to multiplying by 2, it may seem intuitive to assume shifting right by 1 is equivalent to division by 2.
Consider the binary representation of 6: 110
Shifting right removes the last binary digit, so we have 11 which is binary of 3, indeed a division by 2.
Now, consider 101. This is 5 in binary. Shifting right by 1 bit removes the last 1, leaving 10, which is binary of 2. But we know 5÷2 = 2.5, not 2. What has happened is that the binary digits are integer representations. The fractional part has been truncated because it cannot be represented as an integer. This is why the shift operations work very well with integers.
Shifting right by 1 bit, then, truncates the fractional part of the result of division by 2, leaving the integral part.
Step-by-step explanation:
Given
a : b = 5 : 3
or
a = 5 and b = 3
Now
= <u>5a - 3b</u>
5a + 3b
= <u>5</u><u> </u><u>*</u><u> </u><u>5</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>*</u><u> </u><u>3</u>
5 * 5 + 3 * 3
= <u>2</u><u>5</u><u> </u><u>-</u><u> </u><u>9</u>
25 +9
= 16/ 34
Dividing both numerator and denominator by 2 we get
= 8/17
Let's solve ~
If it passes through x, then let's find x when y = 0
So, required values of x are 3 and -2
Now, let's differentiate the equation to get slope slope for tangent ~
Now, plug in the values of x to find slopes of tangents
and
We know, tangent are normal are perpendicular. so let's find out slopes of normals m1' and m2'
and
Now, write the equations of normals using point slope form :
Normal 1 : passing through (3 , 0), and slope = -1/5
and
Normal 2 : passing through (-2 , 0), and slope = 1/5
That's all for Aunty ~ hope it helps !
Answer:
Total houses = 54
House sold last month = 1/3 * 54 = 18
Remaining houses = 54-18 = 36
Houses sold this month = 5/6* 36 = 30 houses
House left to be sold = 36 - 30 = 6 houses