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PIT_PIT [208]
3 years ago
9

The melting point of nitrogen is

Mathematics
1 answer:
Anika [276]3 years ago
7 0

Answer:

-250°F

Step-by-step explanation:

-346°F / -96°F = -250°F

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2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
4 years ago
What is the sum of 1/8 + 5/16 + 3/8<br><br> 9/32<br> 13/32<br> 9/16<br> 13/16
den301095 [7]

11/16 sorry I’m stxxupid

6 0
3 years ago
Read 2 more answers
How do you find the zeros of an equation​
lubasha [3.4K]

Answer:

Step-by-step explanation:

In general, given the function, f(x), its zeros can be found by setting the function to zero. The values of x that represent the set equation are the zeroes of the function. To find the zeros of a function, find the values of x where f(x) = 0.

5 0
3 years ago
Read 2 more answers
The radius of the sphere is 33 find the surface area
patriot [66]

Answer:

A=13684.7776

Step-by-step explanation:

= 4\pi {r}^{2}

4\pi {33 }^{2}  = 13684.7776

5 0
3 years ago
Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

W(-1, 1) = (x_1, y_1)

X(1, 2) = (x_2, y_2)

Plug in the values

WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}

WX = \sqrt{(2)^2 + (1)^2}

WX = \sqrt{4 + 1}

WX = \sqrt{5}

WX = 2.24

✔️Distance between X(1, 2) and Y(2, -4)

Let,

X(1, 2) = (x_1, y_1)

Y(2, -4) = (x_2, y_2)

Plug in the values

XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}

XY = \sqrt{(1)^2 + (-6)^2}

XY = \sqrt{1 + 36}

XY = \sqrt{37}

XY = 6.08

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

Y(2, -4) = (x_1, y_1)

Z(-2, -1) = (x_2, y_2)

Plug in the values

YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}

YZ = \sqrt{(-4)^2 + (3)^2}

YZ = \sqrt{16 + 9}

YZ = \sqrt{25}

YZ = 5

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

Z(-2, -1) = (x_1, y_1)

W(-1, 1) = (x_2, y_2)

Plug in the values

ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}

ZW = \sqrt{(1)^2 + (2)^2}

ZW = \sqrt{1 + 4}

ZW = \sqrt{5}

ZW = 2.24

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0
4 years ago
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