We want double sixes. This means that we want both the first roll and the second roll to be 6.
The given point is given as (r1 , r2) where:
r1 is output from first roll
r2 is output from second roll
Since we want both outputs to be 6, therefore, the answer would be: (6,6)
Alright
so
28% of 2 m³=0.28 times 2=0.56 m³ of silt in the first mixture
13% of the 1 m³=0.13 times 1=0.13 m³ of silt in 2nd
total is 0.56 m³+0.13 m³=0.69 m³ of silt
and the total is 2m³+1m³=3m³
so
0.69/3=0.23=23%
answer is D
Answer:
Follows are the solution to the given question:
Step-by-step explanation:
There are missing details, which is why its solution is as follows:
When an angle bisector points so, its two sides of the corner are equidistant. Its corner bisector of a triangle angle is a straight line splitting its angle into two congruent directions. In such a single point, calling its incentives, follow three-angle engineers are required of its three triangle angles.
Answer:
.837537537 =
837537537
1000000000
Step-by-step explanation:
