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Wittaler [7]
2 years ago
10

X³ by a³ + a³by x³=p x³by a³- a³by ³=q eliminate x

Mathematics
1 answer:
sasho [114]2 years ago
6 0

Answer:

Step-by-step explanation:

\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4

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1. A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?
andrew-mc [135]

The four quadrants and the sign of coordinates is given as follows:

Quadrant I : (n, n ) both x and y positive.

Quadrant II : ( -n,n) = x negative and y positive.

Quadrant III : ( -n,-n) = both x and y negative.

Quadrant IV: (n, -n) = x positive and y negative.

So Based on the above concept , we can say that vertex C (-n,-n) has both x and y negative and so it lies in quadrant III.

Answer is Vertex C (-n,-n)

5 0
3 years ago
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I had four numbers: 12, 8, 4, and ????? However, I remember that their average was 11. Please, help me to remember the number th
Anestetic [448]

Answer:

The number was 20

Step-by-step explanation:

As the average is 11 and the numbers are 4, so the total sum of numbers will be 11X4=44. now the sum of three numbers are (20+8+4)=24. So the last number will be= (44-24)=20. :)

5 0
3 years ago
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Is it a function and whats the domain and range?<br>Picture below
ipn [44]

Answer:

This is not a function

The domain is 3,6,-7,6,-3

The range is -6,-4,5,1,2

Step-by-step explanation:

This is not a function because the x value 6 is on the x list twice which means that a x value touches the y value twice so this is not a function

Hoped this helped :)

Mark me as brainllest thx

7 0
2 years ago
I need help with this please.
quester [9]
Nothing is attached I cannot
4 0
3 years ago
Y=-6/5x +4 <br> y-= -1/5x -1
Komok [63]

Answer: (5,-2)

Step-by-step explanation:

I'm assuming the equations are:

Y=-(6/5)x +4

y = -(1/5)x -1  [Note that I changed "y-" to just "y."]

We can solve this in one of two ways:  Mathematically and Graphically.

<u>Math:</u>  

y = -(1/5)x -1

6y = -(6/5)x -6

-<u>(Y=-(6/5)x +4)</u>

5y = -10

<u>y = -2</u>

y = -(1/5)x -1

-2 = -(1/5)x -1

-1 = -(1/5)x

5 = x

<u>x = 5</u>

<u></u>

The solution is (5,-2)

<u>Graph:</u>

<u></u>

See the attached graph.  The lines intersect at (5,-2)

5 0
3 years ago
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