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likoan [24]
2 years ago
7

Let Xi = (i =1,2,3) be independently and normally distributed random variable with mean of 4 as variance i. state the distributi

on of the following random variable
i) V = X1+X2+X3
Mathematics
1 answer:
puteri [66]2 years ago
3 0

The sum of normally distributed random variables is also a normally distributed random variable.

Given n random variables with X_i\sim\mathrm{Normal}(\mu_i,\sigma_i^2), their sum is

\displaystyle\sum_{i=1}^n X_i \sim \mathrm{Normal}\left(\sum_{i=1}^n \mu_i, \sum_{i=1}^n \sigma_i^2\right)

i.e. normally distributed with mean and variance equal to the sums of the means and variances of the X_i.

In this case, each of X_1,X_2,X_3 are normally distributed with \mu=4 and \sigma^2 = ... I'm not sure what you meant for the variance, so I'll keep it symbolic. Then

V = X_1+X_2+X_3 \sim \mathrm{Normal}(12, 3\sigma^2)

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mario62 [17]

Answer:⬛️=.667 (.66 repeating)

Step-by-step explanation) you can set up the equation:

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now get x by itself by dividing both sides by 3

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3 years ago
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snow_lady [41]

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Step-by-step explanation:

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3 years ago
S=4lw+2wh; s=200, l=9, w=5
goldfiish [28.3K]

Answer:

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