Answer:
Step-by-step explanation:
Consider car 1 with mass and original speed and car 2 with mass and original speed . We can consider both cars as punctual masses. In this case, recall that the kinetic energy of a particle of mass and speed is given by the expression . Then, since car 1 has twice the mass of a second car, but only half as much kinetic energy based on the description, we have the following equations.
, .
Replacing the equation in the second one, leads to , which implies Since and assuming that both speeds are positive, then .
Given that, if both cars increase their speed by 5.5 m/s then they have the same kinetic energy, we have that
. Using the previous result, and expressing everything in terms of and we have that
(where cancells out).
Then, we have the following equation , which by algebraic calculations leads to . Since we assumed , we have that .Then,
In this situation, the cases are the bags or each piece of baggage.
<h3>What is a case?</h3>
In statistics, the word case is used to refer to the individual from which data is collected. For example, in a study about students' performance, the cases are each of the students.
<h3>What is the case in this situation?</h3>
Considering the administrators will need to weight and record each bag, the cases are each piece of baggage.
Note: This question is incomplete; here are the missing options:
A. Number of bags weighing more than 75 pounds.
B. Average weight of the bags.
C. Each piece of baggage.
D. The airport administrators.
Learn more about statistics in brainly.com/question/8058700
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Answer:
120 deet above ground level
Step-by-step explanation:
180 - 60 = 120
<span>The expressions that cannot be factored using integral coefficients and integral constants is the below:
</span>b. 2x2 + x + 4
d. x2 - 2x - 4
For a. 25x2 - 40x + 16 the factors are (5x – 4) (5x – 4)
For c. 6x2 - 2x - 20 the factors are (2x - 4) (3x + 5)
<em>11 2/5 mm³</em>
- Step-by-step explanation:
<em>Hi there ! </em>
<em />
<em>3 4/5mm³ = (3×5 + 4)/5 = (15 + 4)/5 = 19/5 mm³</em>
<em />
<em>19/5 mm³ ............. 1/3 box</em>
<em>x mm³ .......................1 box</em>
<em>x = 19/5×1 : 1/3</em>
<em>= 19/5 × 3/1</em>
<em>= 19×3/5</em>
<em>= 57/5</em>
<em>= 11 2/5 mm³</em>
<em />
<em>Good luck !</em>