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Andreas93 [3]
2 years ago
14

If an event has a 55% chance of happening in one trial, how do I determine the chances of it happening more than once in 4 trial

s?
Mathematics
1 answer:
aev [14]2 years ago
6 0

The chances of it happening more than once in 4 trials is 13%

<h3>How to determine the number</h3>

From the information given, we have can deduce that;

Probability of 1 trial = 55%

= 55/ 100

Find the ratio

= 0. 55

We are to find the probability of it happening more than once in 4 different trials

If the probability of it happening in one trial is 555 which equals 0. 55

Then the probability of it happening in 1 in 4 trials is given as;

P(1/4 trials) = 1/ 4 × 55%

P(1/4 trials) = 1/ 4 × 0. 55

Put in decimal form

P(1/4 trials) = 0. 25 × 0. 55

P(1/4 trials) = 0. 138

But we have to know the percentage

= 0. 138 × 100

Multiply the values, we have

= 13. 8 %

Thus, the chances of it happening more than once in 4 trials is 13%

Learn more about probability here:

brainly.com/question/24756209

#SPJ1

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irina1246 [14]

The average rate of change of the function from x = 0 to x = 2 is -2

From the complete question (see attachment), we have the following ordered pair when x = 0 and x = 2

(x,y) = \{(0,10)\ (2,6)\}

The average rate of change is calculated using:

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So, we have:

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Divide -4 by 2

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Hence, the average rate of change of the function from x = 0 to x = 2 is -2

Read more about rate of change at:

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Can anyone help me please?
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Step-by-step explanation:

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