B. Multiplying both sides of the equation by 3
Answer:
7/44
Step-by-step explanation:
you can't simply subtract 1/11 from 1/4 because the denominators are not the same . Meaning you have to convert the denominators into a similar number. Transformers in even number and a consecutive number while 11 is an odd number and a prime number they don't really agree on anything 11 can only be divided by itself and 1 wall for can be divided by a multitude of things. Because of them not exactly agreeing on any specific category , you have to multiply them by each other . So your new fractions should look like 11 / 44 and 4 / 44 . from there you can easily subtract 4 from 11 and get 7 / 44 now normally you can reduce these types of fractions but because seven can only be divided by itself and 44 is not a factor of 7 you cannot reduce this fraction .
if the diameter is 20, the its radius must be half that or 10.
![\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=5\pi \\ r=10 \end{cases}\implies \begin{array}{llll} 5\pi =\cfrac{\theta \pi (10)^2}{360}\implies 5\pi =\cfrac{5\pi \theta }{18} \\\\\\ \cfrac{5\pi }{5\pi }=\cfrac{\theta }{18}\implies 1=\cfrac{\theta }{18}\implies 18=\theta \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20sector%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%5E2%7D%7B360%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3D%5Cstackrel%7Bdegrees%7D%7Bangle%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20A%3D5%5Cpi%20%5C%5C%20r%3D10%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%205%5Cpi%20%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20%2810%29%5E2%7D%7B360%7D%5Cimplies%205%5Cpi%20%3D%5Ccfrac%7B5%5Cpi%20%5Ctheta%20%7D%7B18%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B5%5Cpi%20%7D%7B5%5Cpi%20%7D%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%201%3D%5Ccfrac%7B%5Ctheta%20%7D%7B18%7D%5Cimplies%2018%3D%5Ctheta%20%5Cend%7Barray%7D)
Step-by-step explanation:
From the statement:
M: is total to be memorized
A(t): the amount memorized.
The key issue is translate this statement as equation "rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized"
memorizing rate is 
.
the amount that is left to be memorized can be expressed as the total minus the amount memorized, that is 
.
So we can write
And that would be the differential equation for A(t).
Answer:
y = 4x-9
Step-by-step explanation:
16x-4y-36 = 0
-4y = -16x+36(subtract 16x from both sides and add 36)\
y = 4x-9(divide both sides by -4)
