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4 years ago

0.75x10= what is the answer.

Mathematics

2 answers:

ahrayia [7]4 years ago

7 0

Answer:

7.5

Step-by-step explanation:

Anything times 10 you should just add an invisible digit to the end and move everything one over. That way from 0.75, you can get 7.5.

kvv77 [185]4 years ago

6 0

Answer:

7.5

Step-by-step explanation:

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Identify if the line has a positive or negative slope. Calculate the slope of the line 2y = x - 8

saul85 [17]

Answer: m = 1/2

Step-by-step explanation: To find the slope of the line, we would first put the equation in y = mx + b form to get y by itself on the left side.

So divide both sides by 2 to get y = 1/2x - 4.

Now the slope is the coefficient of the x term which is 1/2.

This is a positive slope.

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3 years ago

What 3 numbers multiply to get 63?

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There are many combinations if the numbers are not required to be integers.

If they are required to be integers, I'd suggest:

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3 years ago

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30 points if you answer this!

lord [1]

Answer:

Step-by-step explanation:

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3 years ago

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A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

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