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allsm [11]
2 years ago
5

A body and tackle with a velocity ratio of 5 is used to raise a mass of 50kg through a vertical distance of 20n at a steady rate

if the effort is equal to 80n. Determine (a) distance moved by effort (b)the workdone by the effort in lifting the load (c)the losses in energy involve the operating in machine
Mathematics
1 answer:
matrenka [14]2 years ago
7 0

a. Distance moved by effort = 1 meter

b. Work done by effort = 80 Joules

c. Losses in energy = 18 Joules

<h3>How to determine the parameters</h3>

a. Note that velocity ratio is defined as the ratio of a distance through which any part of a machine moves to the distance moved by its parts

Velocity ratio = distance moved by the effort/distance moved by the body

Where velocity ratio = 5

vertical distance = 20cm

Distance moved by effort = 5 × 0. 20 = 1 meter

b. Formula for work done is given as ;

Work done = Effort × distance moved by effort

Work done = 80 × 1

Work done = 80 Newtons

c. First, let's find the work output

Work output = m g h

Work output = 50 × 9.8 × 0. 20

Work output = 98 Joules

Losses in energy = Work output - work done

Losses in energy = 98 - 80

Losses in energy = 18 Joules

Learn more about work done here:

brainly.com/question/25573309

#SPJ1

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Answer:

0.216 = 0.6³

Step-by-step explanation:

using the rule of logarithms

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log_{0.6} 0.216 = 3 ⇒ 0.216 = 0.6^{3}


3 0
3 years ago
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A box contains four 10 nf and eight 100 nf capacitors. (a) what is the probability of obtaining at least two 10 nf capacitors if
grigory [225]

there are 4 of the 10-nf and 8 of the 100-nf capacitors which is a total of 12 items.

the probability of drawing a 10-nf is: 4 out of 12 = \frac{1}{3}

the probability of drawing a 100-nf is: 8 out of 12 =  \frac{2}{3}

(a)  "at least two" means: 2 or 3 or 4

Probability of 2 (10's) and 2 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{2}{3} x \frac{2}{3} = \frac{4}{81}

Probability of 3 (10's) and 1 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{1}{3} x \frac{2}{3} = \frac{2}{81}

Probability of 4 (10's) and 0 (100's):  \frac{1}{3} x \frac{1}{3} x \frac{1}{3} x \frac{1}{3} = \frac{1}{81}

2 or 3 or 4: \frac{4}{81} + \frac{2}{81} + \frac{1}{81} = \frac{7}{81}

(b) without replacement

Probability of 2 (10's) and 2 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{8}{10} x \frac{7}{9} = \frac{4 x 3 x 8 x 7}{12 x 11 x 10 x 9}

Probability of 3 (10's) and 1 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{2}{10} x \frac{8}{9} = \frac{4 x 3 x 2 x 8}{12 x 11 x 10 x 9}

Probability of 4 (10's) and 0 (100's):  \frac{4}{12} x \frac{3}{11} x \frac{2}{10} x \frac{1}{9} = \frac{4 x 3 x 2 x 1}{12 x 11 x 10 x 9}

2 or 3 or 4: \frac{4 x 3 x 8 x 7}{12 x 11 x 10 x 9} + \frac{4 x 3 x 2 x 8}{12 x 11 x 10 x 9} + \frac{4 x 3 x 2 x 1}{12 x 11 x 10 x 9} = \frac{672 + 192 + 24}{12 x 11 x 10 x 9} =  \frac{888}{12 x 11 x 10 x 9}  =  \frac{111}{1485}


8 0
3 years ago
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Which of the following graph shows a negative linear relationship with a correlation coefficient ,r, relatively close to -1
torisob [31]

Answer:

where's the graph ??

Step-by-step explanation:


8 0
3 years ago
Combine like terms to simplify the expression:<br> -6 + 8 − 3x + 13x
eimsori [14]

Answer:

10x+2

Step-by-step explanation:

-3x and 13x are like terms and -3x+13x=10x

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3 0
3 years ago
This high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards
liberstina [14]

Answer:

Given : The high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide.

The school decided to cover the semicircles with grass to create a space for stretching and other activities.

To Find: area of one of the semicircles at either end of the track

How many square yards of grass will the school need to cover the entire circle?

Solution:

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Radius of semicircle = 70/2 = 35 yards

Area of semicircle at one end = (1/2)πr²

= (1/2)(22/7)35²

= 1,925 sq yards

area of one of the semicircles at either end of the track = 1,925 sq yards

square yards of grass will the school need to cover the entire circle

= 2 x   1,925

= 3850 sq yards

distance around one of the semicircles at either end of the soccer field = πr  = (22/7) 35 = 110 yards

distance around the inner lane of the track  = 100 + 100 + 110 + 110

= 420 yards

Please Mark as Brainliest

Hope this Helps

4 0
3 years ago
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