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allsm [11]
2 years ago
5

A body and tackle with a velocity ratio of 5 is used to raise a mass of 50kg through a vertical distance of 20n at a steady rate

if the effort is equal to 80n. Determine (a) distance moved by effort (b)the workdone by the effort in lifting the load (c)the losses in energy involve the operating in machine
Mathematics
1 answer:
matrenka [14]2 years ago
7 0

a. Distance moved by effort = 1 meter

b. Work done by effort = 80 Joules

c. Losses in energy = 18 Joules

<h3>How to determine the parameters</h3>

a. Note that velocity ratio is defined as the ratio of a distance through which any part of a machine moves to the distance moved by its parts

Velocity ratio = distance moved by the effort/distance moved by the body

Where velocity ratio = 5

vertical distance = 20cm

Distance moved by effort = 5 × 0. 20 = 1 meter

b. Formula for work done is given as ;

Work done = Effort × distance moved by effort

Work done = 80 × 1

Work done = 80 Newtons

c. First, let's find the work output

Work output = m g h

Work output = 50 × 9.8 × 0. 20

Work output = 98 Joules

Losses in energy = Work output - work done

Losses in energy = 98 - 80

Losses in energy = 18 Joules

Learn more about work done here:

brainly.com/question/25573309

#SPJ1

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<h2>$ 22200 in higher yielding bank and $ 44400 in lower yielding bank</h2>

Step-by-step explanation:

       Jolene invests in two bank accounts. The first account gives a 4% interest per year and the second bank gives a 10% interest rate per year.

       She puts twice as much in the lower yielding bank account. Let us denote the amount put in high yielding bank account by x. Lower yielding bank account will have 2x.

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