Answer:
Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:
Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:
Class 66 - 68:
When the computation is completed, the frequency distribution will be:
Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:
<em>See attachment for result of 1-VarStats</em>
First, convert 5 hours into minutes:
5 hours 60 min
------------ * --------------- = 300 min
1 1 hr
Next, find the unit rate in m/min:
9673.6 m
--------------- = 32.24 m/min
300 min
Now find the distance you can walk in 70 minutes at this rate:
32.24 m
------------- * 70 min = 2247 meters (answer)
1 min
You could walk 2247 meters (to the nearest meter) in 70 minutes.
The answer is 19.5
You add all the numbers to get 273 and divide by the amount of dots which is 14 to get 19.5
To get the inverse, first off do a quick switch on the variables, and then solve for "y".
Just look at the top triangles
Angles in a triangle add up to 180°
To find the angle next to 36°:
It shows that all together its a 90° angle so you do 90-36= 54°
To find the angle next to 88°:
Angles on a straight line add up to 180° so you do 180-88= 92°
You now have the 2 of the angles in the triangle with angle 1
You now add these 2 angles so 54+92= 146°
and as angles in a triangle add up to 180° you do 180-146= 34°
So angle 1 is 34°
