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lukranit [14]
3 years ago
15

Avi's pet hamster chubby loves to run in his hamster wheel. during one "race", avi counts 100 rotations of the wheel. she wants

to know how far chubby ran, so she measures the diameter of the wheel and finds that it is 8 space incheshow far did chubby run
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
5 0
If the diameter is 8 inches, the circumference is 8π inches.  So if the pet turned the wheel 100 revolutions the distance traveled is:

d=100(8π) inches

d=800π inches

d≈2513.27 inches
USPshnik [31]3 years ago
5 0

Answer:

Chubby ran a total distance of 6280 cm.

Step-by-step explanation:

Each time the hamster wheel rotates, the distance Chubby runs is equal to the circumference of the wheel.

We can use the formula C = πd to find the circumference of the wheel.

C  =πd

=π(20)

=20π

The circumference of Chubby's wheel is 20π cm.

Since the wheel rotated 100 times, the total distance Chubby ran is 100 times the circumference of the wheel:

100 x 20π = 2000π

2000π = 2000 x 3.14

6280

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Which two tables represent the same function?
topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

  (x2 , y2) is \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ \frac{y-8}{x-4}=\frac{7-8}{6-4}

∴ \frac{y-8}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ \frac{y-5}{x-4}=\frac{4-5}{6-4}

∴ \frac{y-5}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ \frac{y-8}{x-2}=\frac{5-8}{8-2}

∴ \frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

∴ x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

∴ \frac{y-10}{x-2}=\frac{14-10}{6-2}

∴ \frac{y-10}{x-2}=\frac{4}{4}======\frac{y-10}{x-2}=1

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

∴ x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6

∴ \frac{y-9}{x-2}=\frac{6-9}{8-2}

∴ \frac{y-9}{x-2}=\frac{-3}{6}======\frac{y-9}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

∴ The 1st and the 5th tables represent the same function

3 0
3 years ago
Brandon rode his bike 90% of the distance that Carlee rode her bike this week. Brandon rode 58.5 miles. How many miles did Carle
kramer
Carlee rode 52.65 miles this week.
8 0
3 years ago
Which function is represented by the graph
fiasKO [112]

Answer:

Step-by-step explanation:The answer is C

6 0
3 years ago
-3/4x>12 solve for x​
Ad libitum [116K]

Answer:

\Huge\boxed{\mathsf{\rightarrow X

Step-by-step explanation:

\Large\boxed{\mathsf{SUBJECT: MATH}}

Isolate x on one side of the equation.

Find the value of x.

First, multiply -1 from both sides.

(-3/4x)(-1)<12(-1)

Solve.

12(-1)=-12

3/4x<-12

Next, multiply 4 from both sides.

4*3/4x<4(-12)

Solve.

Multiply the numbers from left to right.

4(-12)=-48

3x<-48

Then, divide by 3 from both sides.

3x/3<-48/3

Solve.

Divide the numbers from left to right.

-48/3=-16

X<-16

\Large\boxed{\Rightarrow \mathsf{X

The correct answer is x<-16.

6 0
2 years ago
The engine torque y (in foot-pounds) of one model of car is given by y=−3.75x2+23.2x+38.8, where x is the speed (in thousands of
Stels [109]

Answer:

Step-by-step explanation:

If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8

The engine speed is at maximum if dy/dx = 0

dy/dx = -2(3.75)x+23.2

dy/dx = -7.5x + 23.2

since dy/dx = 0

0 =  -7.5x + 23.2

7.5x = 23.2

x = 23.2/7.5

x = 3.093

Hence the maximum torque is 3.09 rev/min

8 0
3 years ago
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