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notka56 [123]
2 years ago
8

Three neon lights are turned on at the same time. One blinks every 4 seconds, the second one blinks every 5 seconds, and the thi

rd blinks every 6 seconds. In 5 minutes, how many times will all three lights blink at the same time?
Mathematics
1 answer:
emmasim [6.3K]2 years ago
4 0

In order to find how many times they will blink at the same time we need to find the common multiple of 4 and 6 between 1 and 60.

The first bulb blinks after every 4 seconds, means it blinks in multiple of 4.

The multiples of 4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60.

The second bulb blinks after every 6 seconds, means it blinks in multiple of 6.

The multiples of 6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60.

The common multiple of 4 and 6 = 12, 24, 36, 48, 60.

∴

in sixty seconds they will blink 5 times at the same time.

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I need an answer ASAP I will thank you and give you a like!
LenaWriter [7]

Answer:

Option C. As x approaches positive infinity, f(x) approaches positive infinity, and g(x) approaches negative infinity.

Step-by-step explanation:

we know that

Observing the table

The function f(x) is a increasing function

As the value of x increases, the value of f(x) increases

so

As x approaches positive infinity, f(x) approach positive infinity

<em>Find the slope of the linear equation g(x)</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the points (6, -2) and (3, 7)

substitute

m=\frac{7+2}{3-6}

m=\frac{9}{-3}=-3

The slope of the linear equation g(x) is negative

That means ----> Is a decreasing function

As the value of x increases, the value of g(x) decreases

so

As x approaches positive infinity, g(x) approach negative infinity

therefore

As x approaches positive infinity, f(x) approaches positive infinity, and g(x) approaches negative infinity.

6 0
3 years ago
Mary had $25,000 to invest. She invested part of that amount at 3% annual interest and part at 5% annual interest for one year.
emmasim [6.3K]
(25000-f)(.03)+.05f=1100

750-.03f+.05f=1100

750+.02f=1100

.02f=350

f=$17500

So Mary invested $17500 @ 5% and 7500 at 3% to earn $1100 in interest.


3 0
3 years ago
How much larger is 6.3 x 10^6 than 4.9 x 10^4 ?
antoniya [11.8K]

Answer: 625100

Step-by-step explanation:

To begin, we would start multiply both numbers one by one.

(6.3 x 10^6) - 4.9 x 10^4

6.3 x 10^6 = 6300000

4.9 x 10^4 = 49000

Now, subtract (6.3 x 10^6) and (4.9 x 10^4)

                          6300000.            49000

6300000 - 49000 = 6251000

8 0
3 years ago
Explain how you know if an equation has one solution, infinitely many solutions, or no solution
lubasha [3.4K]
No solution would mean that there is no answer to the equation. It is impossible for the equation to be true no matter what value we assign to the variable. Infinite solutions would mean that any value for the variable would make the equation true. :)
8 0
2 years ago
A parent made x cupcakes for each of the 109 students in the fourth grade. Which expression could be used to determine the total
larisa86 [58]

109x is the expression that could be used to determine the total number of cupcakes made given that a parent made x cupcakes for each of the 109 students in the fourth grade. This can be obtained by forming the algebraic expression for the given conditions.

<h3>Find the required expression:</h3>
  • Algebraic expression is made up of numbers, operations and variables.
  • Algebraic expression is true for all values of x.
  • For example, 2x, 5x + 9 etc.

Given that,

A parent made x cupcakes for each of the 109 students in the fourth grade.

The total number of students in the class = 109

The number of cupcakes one student gets = 1 × x = x

⇒ The number of cupcakes 109 student gets = 109 × x = 109x

Hence 109x is the expression that could be used to determine the total number of cupcakes made given that a parent made x cupcakes for each of the 109 students in the fourth grade.

Learn more about algebraic expression here:

brainly.com/question/953809

#SPJ1

7 0
1 year ago
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