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sesenic [268]
3 years ago
5

I answered all my work correctly but I don’t understand this one.

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0
Take your x values in each coordinate and subtract 2, and take your y values and subtract 1.

Q (0-2), (-1-1)
= (-2,-2)

D (-2-2), (2-1)
= (-4, 1)

V (2-2), (4-1)
= (0,3)

J (3-2), (0-1)
= (1,-1)

You can also draw it on a graph and then translate all coordinates 2 units left and 1 down to see the end results.
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What is the domain of the funxtion f(x)=x+1/x^2-6+8
bija089 [108]

Answer:

que??

Step-by-step explanation:

spania spania??

1111

6 0
3 years ago
in the year 2010, the luxury bike industry had two bike manufactures splendor and passion with the market shares of 30% and 70%,
kari74 [83]

Answer: 50%

Step-by-step explanation:

In 2010, there were only 2 bike manufacturers and they had market shares of 30% and 70%.

A new manufacturer joins the market and captures 10% of the market share and Splendor increases to 40% of market share.

Market shares:

Yamaha = 10%

Splendor = 40%

Passion = 100% - 10% - 40%

= 50%

8 0
3 years ago
Three times a number plus 12 minus 5 times the same number is 22. What is the number?​
Ilia_Sergeevich [38]

Answer:3

Explanation: 3x5=15+12=27-5=22

5 0
3 years ago
What number has the same value of 28 tens
iren2701 [21]
The answer is 280 this is your answer
5 0
3 years ago
Read 2 more answers
Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a
jeka57 [31]

Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

Recall that a\cdot b, b\cdot b are both real numbers, so by solving the value of γ, we get that

\gamma= \frac{a\cdot b}{b\cdot b}

By construction, this γ is unique if b\neq 0, since if there was a \gamma_2 such that (a-\gamma_2b)\cdot b = 0, then

\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma

6 0
3 years ago
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