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2 years ago

Drag each group of primates to where they are distributed on the map today.

SAT

1 answer:

kirill115 [55]2 years ago

4 0

North/South America:

New World monkeys inhabit the New World, which includes North and South America.

Africa and Asia:

Prosimians, the earliest of the primates, inhabit regions of Africa and Asia.

Old World monkeys still live in Africa and Asia. Fossil species also lived in Europe.

Apes are Old World primates. They are found today in Africa and Asia.

<h3>What is the group of Primates?</h3>

The primates are;

- New World monkeys

- Prosimians

- Old World monkeys

- Apes

The groups are;

North/South America

Africa and Asia

New World monkeys inhabit the New World, which includes North and South America.

Prosimians, the earliest of the primates, inhabit regions of Africa and Asia. This also applies to Apes and Old monkeys.

Thus;

North/South America:

New World monkeys inhabit the New World, which includes North and South America.

Africa and Asia:

Prosimians, the earliest of the primates, inhabit regions of Africa and Asia.

Old World monkeys still live in Africa and Asia. Fossil species also lived in Europe.

Apes are Old World primates. They are found today in Africa and Asia.

Read more about Primate Groups at; brainly.com/question/11204777

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The questions on a test consist of 10 multiple choices, 3 essays, and 9 free responses. If the questions are ordered randomly, w

kiruha [24]

Answer:

9/22 or 40.9%

Explanation:

Probability describes the likelihood of an event. To find simple probability, like in this question, use division.

To find the probability of the first question being a free response, you first need to find the total number of questions. This can be done by adding together all of the given information. There are 10 multiple choice, 3 essays, and 9 free responses.

10 + 3 + 9 = 22

This means that there are 22 total questions. Next, find how many of these questions are free-response. We know that there are 9 free responses and 22 questions in total. So, 9 out of 22 are free responses. This can be rewritten as 9/22.

If you want to find the percentage, simplify the fraction and convert it to a percentage.

9/22 = 0.409

Then, move the decimal 2 places to the right. This gives you 40.9%, which is the probability of the first question being a free-response.

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2 years ago

What is the term used to describe the distribution of a data set with one mode

Veseljchak [2.6K]

Unimodal

A unimodal distribution is a distribution with one clear peak or most frequent value.

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How many different nth roots does a nonzero complex number have?

Reika [66]

The Complex nth Roots Theorem with any nonzero complex number has exactly n ∈ N distinct nth roots.

<h3>What is a non-zero complex number?</h3>

This is the quantity which does not equal zero is said to be nonzero. A real nonzero number must be either positive or negative, and a complex nonzero number can have either real or imaginary part nonzero.

The roots lie on a circle of radius centered at the origin and spaced out evenly by angles of 2π/n.

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the distribution of lengths of salmon from a certain river is approximately normal with standard deviation 3.5 inches. if 10 per

juin [17]

Complete question;

<em>The distribution of lengths of salmon from a certain river is approximately normal with a standard deviation of 3.5 inches. If 10 percent of salmon are longer than 30 inches, which of the following is closest to the mean of the distribution? 26 inches A 28 inches B 30 inches C 33 inches D 34 inches</em>

Option B is correct. The value that is closest to the mean of the distribution is 30inches.

The formula for calculating the z-score is expressed as:

$z=\frac{ x-\mu}{\sigma}$

Given the following parameters

$\sigma = 3.5\\x = 26in$

If 10 percent of salmon are longer than 30 inches, then:

P(x>30) = 0.1

Using the z table to get the value corresponding to the mean area 0.1.

The required z-score will be -1.285

Substitute the resulting parameters into the formula to get the mean of the distribution.

$z=\frac{x-\mu}{\sigma}\\-1.285=\frac{26-\mu}{3.5}\\-1.285 \times 3.5 = 26 - \mu\\ -4.4975 = 26 - \mu\\\mu = 26 + 4.4975\\\mu = 30.4975\\\mu \approx 30in$

Hence the value that is closest to the mean of the distribution is 30inches.

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In 2015 attackers targeted six locations throughout paris

Ganezh [65]

These attackers sought to create political pressure within France to suspend airstrikes against ISIS targets within Syria.

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In 2015, ISIS attackers targeted six (6) different locations throughout Paris, so as to create political pressure within France for the suspension of airstrikes against Islamic State of Iraq (ISIS) targets within Syria.

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