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damaskus [11]
2 years ago
14

tiff basic insurance cost is $613.50 per year. His insurance company offers a typical "safe-driver discount." What would be his

rate if he went three years without an accident? Annual premium?
Mathematics
1 answer:
forsale [732]2 years ago
5 0

The rate if he went three years without an accident based on the information about the insurance is $552.15.

<h3>How to calculate the insurance?</h3>

From the information given, his basic insurance cost is $613.50 per year and his insurance company offers a typical "safe-driver discount.

The amount will be:

= 613.50 - (20.45 × 3)

= 552.15

In conclusion, the rate is $552.15.

Learn more about insurance on:

brainly.com/question/25855858

#SPJ1

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I'm doing the same one right now lol, also if anyone gives you a link , don't open it . it can be a hacker . Step-by-step explanation:

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3 years ago
A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting
Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= \frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees}  = \frac{6}{15}

b.) The probability that a secretary wins a ticket on second draw.  It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant  wins on first draw)

=\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}

= \frac{\frac{5}{15}  \times \frac{6}{14}}{\frac{5}{15} }  = \frac{6}{14}  .

The probability that  a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw  = \frac{6}{15} is not true.

The probability that a secretary wins on the second draw  = \frac{number \hspace{0.1cm} of  \hspace{0.1cm} secretaries  \hspace{0.1cm} remaining } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} remaining}  = \frac{6 - 1}{15 - 1}  = \frac{5}{14}

c.) The probability that a consultant wins on the first draw  =

\frac{number \hspace{0.1cm} of  \hspace{0.1cm} consultants  \hspace{0.1cm}  } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} }  = \frac{5 }{15}  = \frac{1}{3}

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= \frac{6}{15}  \times \frac{5}{14}  = \frac{1}{7}

Therefore the only statement that is not true is b.)

5 0
3 years ago
Which statement is true?
dusya [7]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Symmetry,

Option A.) is correct,

=> N has only the Rotational Symmetry.

7 0
3 years ago
HELP ASAP
Lesechka [4]
452.2 cubic inches!!
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Kai went on a bike ride. Every time he stops to drink water, his bike ride takes 3/4 of a minute longer. If he stops to drink wa
mestny [16]

Answer:

4.5 minutes

Step-by-step explanation:

first convert 3/4 to a decimal so you can multiply it which would be .75

so then .75 times 6=

4.5

5 0
3 years ago
Read 2 more answers
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