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MA_775_DIABLO [31]
2 years ago
15

Please help me, im struggling

Mathematics
1 answer:
Molodets [167]2 years ago
7 0

<u>Part 1</u>

<u />f(a)=4-7a+16a^2

<u>Part 2</u>

<u />f(a+h)=4-7(a+h)+16(a+h)^2\\\\=4-7(a+h)+16(a^2 +2ah+h^2)\\\\=4-7a-7h+16a^2 +32ah+16h^2

<u>Part 3</u>

<u />\frac{f(a+h)-f(a)}{h}=\frac{(4-7a-7h+16a^2 +32ah+16h^2-(4-7a+16a^2)}{h}\\\\=\frac{-7h+32ah+16h^2}{h}\\\\=32a+16h-7

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Step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

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