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MA_775_DIABLO [31]
2 years ago
15

Please help me, im struggling

Mathematics
1 answer:
Molodets [167]2 years ago
7 0

<u>Part 1</u>

<u />f(a)=4-7a+16a^2

<u>Part 2</u>

<u />f(a+h)=4-7(a+h)+16(a+h)^2\\\\=4-7(a+h)+16(a^2 +2ah+h^2)\\\\=4-7a-7h+16a^2 +32ah+16h^2

<u>Part 3</u>

<u />\frac{f(a+h)-f(a)}{h}=\frac{(4-7a-7h+16a^2 +32ah+16h^2-(4-7a+16a^2)}{h}\\\\=\frac{-7h+32ah+16h^2}{h}\\\\=32a+16h-7

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Answer:

  120

Step-by-step explanation:

The dimension across the front in terms of cubes is ...

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8 0
3 years ago
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8 0
3 years ago
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Mashcka [7]

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Step-by-step explanation:

For any two expressions A and B:

If A x B=0  then either A=0 or B=0.

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Hint #22 / 3

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So either (-2x +3)=0(−2x+3)=0 or (-x +3)=0

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(2) ​    −x+3 =0

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In conclusion,  

smaller x  = 3/2

larger x  = 3

5 0
3 years ago
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