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3 years ago

5

Find the area of the shaded composite figure. The apothem on the hexagon is 4√3. Round your answer to the nearest whole number.

**Remember height of a parallelogram is PERPENDICULAR to the base***(Area of parallelogram = bh

1 answer:

oksian1 [2.3K]3 years ago

3 0

Answer:

Step-by-step explanation:

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Jack is playing a game. When a player wins 3 consecutive games, the player receives 10 bonus points and then the player’s total

Paladinen [302]

<span>The function can be described as

b(p)= player receives 10 bonus points
</span>b(p)= p+10<span>

s(p)= increases 5% of the player’s current points
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then </span><span> (s ∘ b)(p) would be
</span><span>s(p)= p*1.05
(s ∘ b)(p)= (p+10)*1.05
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3 years ago

What do i do on this problem?? do i divide or subtract? i'm very confused

Mrrafil [7]

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3 years ago

Read 2 more answers

What is the solution to this equation?

joja [24]

Answer:

A

Step-by-step explanation:

Given

8 - 2x + 6x = 24 , that is

8 + 4x = 24 ( subtract 8 from both sides )

4x = 16 ( divide both sides by 4 )

x = 4 → A

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3 years ago

Which statement about these two sandboxes is true?

adell [148]

A would be the answer

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4 years ago

Make a the subject of a2+b2=c2

wel

Answer:

$a=\sqrt{c^2-b^2$

⇒ $a=\sqrt{(c+b)(c-b)}$ [Factorized form]

Step-by-step explanation:

Given expression:

$a^2+b^2=c^2$

We need to make $a$ the subject.

In order to do that we need to solve the expression for $a$ in terms of $b$ and $c$

We have,

$a^2+b^2=c^2$

Subtracting both sides by $b^2$

$a^2+b^2-b^2=c^2-b^2$

$a^2=c^2-b^2$

Taking square root both sides in order to remove square of $a$

$\sqrt{a^2}=\sqrt{c^2-b^2}$

$a=\sqrt{c^2-b^2$

The difference of squares can be factorized and written as:

$a=\sqrt{(c+b)(c-b)}$ [difference of squares $x^2-y^2=(x+y)(x-y)$ ]

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3 years ago