PLEASE FIND X

What is the sum of the coefficients in the expression below?<br> 22°y2 + 5x+ y2 - 6xy' +7

schepotkina [342]

Answer:

485y to the power 2 + 5x to the power 2 - 6xy to the power 3 + 7

Step-by-step explanation:

I hope this helps. Also, there's this free app called Quick Math. If you need the steps, you should check there first, and maybe you should try that for other math problems as well.

Good luck and have a great rest of your day.

8 0

3 years ago

Is 90 a composite number?

konstantin123 [22]

Answer:

No

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

F(x)=-2x+13 for f(-4) Evaluate

kykrilka [37]

Answer:

Step-by-step explanation:

$f(x)=-2x+13$

To find f(-4), substitute the value of x that's - 4 into f(x). That is for every x in f(x) replace it with - 4

We have

$f( - 4) = - 2( - 4) + 13 \\ = 8 + 13 \\ = 21 \: \: \: \: \: \: \: \:$

We have the final answer as

Hope this helps you

4 0

3 years ago

Find the number of terms, n, of the arithmetic series given a1=11, an=95, and Sn=689.

borishaifa [10]

Answer:

13

Step-by-step explanation:

Its calculate the common difference first.

(95-11)/(n-1).

We also have the sum of these n terms is 689.

So we have the following:

11

+(11+(95-11)/(n-1))

+(11+2(95-11)/(n-1))

+...

+(11+(n-1)(95-11)/(n-1))

This can be re-expressed alittle:

There are (n) amount of 11's in the addition... also 1+2+3+...+(n-1)=(n-1)(n)/2.

So we have the sum is

11(n)+n(n-1)/2×(95-11)/(n-1)

But this equal to 689.

We need to solve the following equation:

11(n)+n(n-1)/2×(95-11)/(n-1)=689

The (n-1)'s in second term can cancel.

11(n)+n/2×84=689

11n+42n=689

53n=689

n=689/53

n=13

4 0

3 years ago

Help with #24!!! I don't get it. Please provide a clear and brief explanation! Thank you <3

Arte-miy333 [17]

So hmmm the band is going to charge her 750, for the whole gig, so that's a fixed amount, regardless of how many folks show up, 2 or 2,000

the caterer, charges 2.25 per head, because, the more heads, the more plates and glasses he has to make, more work for him

now, she wants to keep the charges between 2.75 and 3.25

now.. let's see her costs

750 from the band and 2.25 per head from the caterer, let's say "p" folks show up, so the caterer will then be charging 2.25*p or 2.25p

so her cost say C(p) = 750 + 2.25p

now, we dunno what C(p) is going to end up being, that depends on how many folks show up

now, we know "p" folks are going to show up, so, if "p" show up, the average cost will then be price * p

if the price, Natasha has in mind is 2.75, then C(p) is 2.75p
if the price, Natasha has in mind is 3.25, then C(p) is 3.25p

but whatever 750 + 2.25p is, is ok if it's greater than 2.75p
2.75p < 750 + 2.25p

and whatever 750 + 2.25p is, is not ok if it goes over 3.25p, it has to be less

3.23p > 750 + 2.25p

$\bf 2.75p\ \textless \ 750+2.25p\implies 2.75p-2.25p\ \textless \ 750\implies 0.5p\ \textless \ 750
\\\\\\
\cfrac{1}{2}p\ \textless \ 750\implies p\ \textless \ 2\cdot 750\implies \boxed{p\ \textless \ 1500}\\\\
-------------------------------\\\\
3.25p\ \textgreater \ 750+2.25p\implies 3.25p-2.25p\ \textgreater \ 750\implies \boxed{p\ \textgreater \ 750}\\\\
-------------------------------\\\\
\begin{cases}
p\ \textless \ 1500\\
p\ \textgreater \ 750
\end{cases}\iff 750\ \textless \ p\ \textless \ 1500\impliedby \textit{using the combined form}$

7 0

4 years ago