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amid [387]
3 years ago
11

Find the number of terms, n, of the arithmetic series given a1=11, an=95, and Sn=689.

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

13

Step-by-step explanation:

Its calculate the common difference first.

(95-11)/(n-1).

We also have the sum of these n terms is 689.

So we have the following:

11

+(11+(95-11)/(n-1))

+(11+2(95-11)/(n-1))

+...

+(11+(n-1)(95-11)/(n-1))

This can be re-expressed alittle:

There are (n) amount of 11's in the addition... also 1+2+3+...+(n-1)=(n-1)(n)/2.

So we have the sum is

11(n)+n(n-1)/2×(95-11)/(n-1)

But this equal to 689.

We need to solve the following equation: ​

11(n)+n(n-1)/2×(95-11)/(n-1)=689

The (n-1)'s in second term can cancel.

11(n)+n/2×84=689

11n+42n=689

53n=689

53n=689

n=689/53

n=13

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Two bags with 3 oranges in each bag is the same amount as 3 bags with 2 oranges in each bag. Which property of multiplication do
kodGreya [7K]

Answer:

Commutative Property

Step-by-step explanation:

The property of multiplication that is being demonstrated is known as Commutative Property. This property basically shows that when multiplying two numbers the actual order in which they are multiplied does not matter and does not affect the result at all. For example, the in this scenario to get the total number of oranges we have to multiply the number of bags by the number of oranges in each bag, but whatever way we do this they equal the same

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Therefore,

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Alisiya [41]

Answer:

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Step-by-step explanation:

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5 0
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VARVARA [1.3K]

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