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Veronika [31]
2 years ago
14

Use the graph to find the local minimum and the local maximum for the given function

Mathematics
1 answer:
Elden [556K]2 years ago
6 0

The local minimum on the interval [-3, 0] is -16, the local maximum on the interval [0, 3] is 4 and the local minimum on the interval [0, 3] is -3

<h3>What is a local minimum?</h3>

In a function, a point located at the local minimum is a point that is at a lower coordinate compared to the other neighboring points

<h3>What is a local maximum?</h3>

In a function, a point located at the local maximum is a point that is at a higher coordinate compared to the other neighboring points

<h3>How to determine the local minimum and the local maximum?</h3>

The complete question is added as an attachment

In the first interval, [-3, 0], the lowest point in the interval is located at (-16, -1.5)

This means that the local minimum on the interval [-3, 0] is -16

In the second interval, [0, 3], the highest maximum in the interval is located at (4, 1)

This means that the local maximum on the interval [0, 3] is 4

In the second interval, [0, 3], the lowest minimum in the interval is located at (0, -3)

This means that the local minimum on the interval [0, 3] is -3

Read more about local minimum and local maximum at:

brainly.com/question/9005728

#SPJ1

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3 0
3 years ago
Liam explains that drawing a yellow card is equivalent to drawing a blue card followed by a red card how many spaces forward or
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Complete question :

designs a board game in which a card is drawn on each turn. • A blue card means move forward 4 squares. • A red card means move back 6 squares. Liam suggests adding some other cards to Sia's game Part A Liam explains that drawing a yellow card is equivalent to drawing a blue card followed by a red card. How many spaces forward or backward does a player move after drawing a yellow card? Justify your answer.

Answer:

2 squares backward

Step-by-step explanation:

Given the rule :

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3 years ago
√(2x+1)<br> Evaluate the integral<br> 2<br> (2x + 1) In (2x + 1)<br> dx.
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