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Paraphin [41]
3 years ago
6

Find the first 4 terms of the sequence defined by this rule: f(n)=4n-7

Mathematics
1 answer:
tatiyna3 years ago
6 0

Answer:

-3, 1, 5, 9

Step-by-step explanation:

f(n) = 4n - 7

f(1) = 4(1) - 7

f(1) = 4 - 7

f(1) = -3

f(2) = 4(2) - 7

f(2) = 8 - 7

f(2) = 1

f(3) = 4(3) - 7

f(3) = 12 - 7

f(3) = 5

f(4) = 4(4) - 7

f(4) = 16 - 7

f(4) = 9

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Selena earned $200 last month babysitting. She used 25 of her earnings to buy a video game. How much did she spend on the video
babymother [125]

Answer:

See below

Step-by-step explanation:

<u>Is that $25 or 35%?</u>

If $25, she spent $25.

If 25%, she spent (0.25)*(200) = $50.

3 0
2 years ago
The chances that it will rain tomorrow are 20% what are the chances that it will not rain?
balandron [24]
Hey!~

The chances that it will not rain "tomorrow" is 80%

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5 0
3 years ago
Question progress<br> Homework Progress<br> The ratio 8:2 in its simplest form is
lidiya [134]

Answer:

4:1

Step-by-step explanation:

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6 0
3 years ago
5. Higher Order Thinking if 1/2 multiplied
Lady bird [3.3K]

Answer:

No

Step-by-step explanation:

1/2 times 1/2 = 1/4

6 0
2 years ago
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
3 years ago
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