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The mass percent of HNO₃ in molarity is 15.76 M.
<h3>Assumption</h3>
Let the mass of the solution be 100 g.
Therefore, the mass of 70% HNO₃ in the solution is 70 g
<h3>Determination of the mole of HNO₃</h3>
- Molar mass of HNO₃ = 1 + 14 + (3×16) = 63 g/mol
Mole = mass / molar mass
Mole of HNO₃ = 70 / 63
Mole of HNO₃ = 1.11 mole
<h3>Determination of the volume of the solution</h3>
- Density of solution = 1.42 g/cm³
Volume = mass / density
Volume of solution = 100 / 1.42
Volume of solution = 70.42 cm³
Divide by 1000 to express in L
Volume of solution = 70.42 / 1000
Volume of solution = 0.07042 L
<h3>Determination of the molarity</h3>
- Volume of solution = 0.07042 L
Molarity = mole / Volume
Molarity = 1.11 / 0.07042
Molarity = 15.76 M
Learn more about molarity:
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