Question

Can someone help me with this pls

Answer 1

$\huge\text{Hey there!}$

$\huge\textbf{What is the quadratic formula?}$

$\rm{x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$

$\textsf{Or even}$

$\rm{ax^2 + bx + c = 0}$

$\huge\textbf{What are we looking for?}$

$\rm{9x^2 + 3x - 2 = 0}$

$\huge\textbf{What are the labels in the equation?}$

$\mathsf{a \rightarrow 9}\\\\\mathsf{b\rightarrow 3}\\\\\mathsf{c \rightarrow -2}$

$\huge\textbf{Solving for your equation:}$

$\rm{x = \dfrac{-(3)\pm \sqrt{3^2 - 4(9)(-2)}}{2a}}$

$\huge\textbf{Simplify it:}$

$\rm{x = \dfrac{-3\pm \sqrt{81}}{18}}$

$\rm{x = \dfrac{1}{3}\ or\ x = - \dfrac{2}{3}}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\frak{\mathsf{x} = \dfrac{1}{3}\ or\ \mathsf{x} = - \dfrac{2}{3}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~$\frak{Amphitrite1040:)}$

Answer 2

Answer:

x = 1/3 or x = -2/3

Step-by-step explanation:

Let's solve your equation step-by-step.

9x2+3x−2=0

For this equation: a=9, b=3, c=-2

9x2+3x+−2=0

Step 1: Use quadratic formula with a=9, b=3, c=-2.

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(3)\pm\sqrt{(3)^2-4(9)(-2)} }{2(9)}$

$x=\frac{-3\pm\sqrt{81} }{18}$

x = 1/3 or x = -2/3