Question

40 points fast For the following set of test scores, identify:

Answer 1

Answer:

 The measure of center would this student want his teacher to use is the

median$= {\bf 75}$

Mean$= {\bf 5}$  ,  Mode$={\bf 82}$  , Range$={\bf40}$  and   Interquartile Range$= {\bf 32}$

Step-by-step explanation:

Given Data set$= 50,55,70,75,82,82,90$

Number of elements in data set$= 7$

To find Mean

The ‘Mean” is the average of a set of numbers.

The "Mean" is computed by adding all of the numbers in the data together and dividing by the number  of elements contained in the data set.

Mean$= \frac{50 +55 +70 + 75 + 82 + 82 + 90} {7 }$

Mean$= \frac{504}{7}$

Mean$= 5$

Median

The “Median” is the middle value of a set of ordered numbers.

Therefore Median$=75$

Mode

The "Mode" for a set of data is the value that occurs most often.

It is not uncommon for a data set to have more than one mode. This happens when two or more  elements occur with equal frequency in the data set.

Therefore Mode$=82$

Range

The "Range" is the difference between the largest value and smallest value in a set of data.

Range$= 90-50$

Range$= 40$

Interquartile Range

The “Interquartile Range” is the difference between smallest value and the largest value of the middle  50% of a set of data.

The "Interquartile Range" is from Q1 to Q3:

To find the interquartile range of a set of data:

The cut the list into four equal parts

. The quartiles are the “cuts”

The interquartile range is the distance between the two middle sets of data

Interquartile Range$= Q_3-Q_1$

Interquartile Range$= 82-50$

Interquartile Range$= 32$