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scoundrel [369]
2 years ago
9

A group of yeast cells grows by 75% every 3hrs. At 9am, there are 200 yeast cells [9 marks].

Mathematics
1 answer:
vodomira [7]2 years ago
7 0

a) The exponential function that models the number of cells is: A(t) = 200(1.75)^{\frac{t}{3}}

b) There will be 1292 cells after 10 hours.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

A(t) = A(0)(1 + r)^{\frac{t}{n}}

In which:

  • A(t) is the amount after t hours.
  • A(0) is the initial amount.
  • r is the rate of change, as a decimal.
  • n is the time it takes to change.

For this problem, the parameters are:

A(0) = 200, r = 0.75, n = 3.

Hence the equation is:

A(t) = A(0)(1 + r)^{\frac{t}{n}}

A(t) = 200(1 + 0.75)^{\frac{t}{3}}

A(t) = 200(1.75)^{\frac{t}{3}}

The number of cells after 10 hours is:

A(t) = 200(1.75)^{\frac{t}{3}}

A(10) = 200(1.75)^{\frac{10}{3}}

A(10) = 1292.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

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10.
Kay [80]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

Step-by-step explanation:

Information provided

\bar X=32.1 represent the sample mean

\mu population mean  

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=83-1=82

The Confidence is given by 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=62.132

\chi^2_{1- \alpha/2}=104.139

And replacing into the formula for the interval we got:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.535 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.2 \leq \sigma \leq 2.8

And the best option would be:

A.  2.2 < σ < 2.8

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3 years ago
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-2i * -3i
6i
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Step-by-step explanation:

If you sliced the pyramid to the base there would still be a triangle left.

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